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Is there away to open a dynamic shape?
I tried axlDBOpenShape(current_shape) and Get "W- *WARNING* (axlDBOpenShape): Cannot edit a generated shape."
I use this to open static shapes and it works fine, but need to be able to open both.
For dynamic shapes, you must open the dynamic shape (BOUNDARY class) not the generated shape (ETCH class).
To obtain the boundary shape from a generate shape (assumes generatedShape is the Skill variable hold the shape dbid)
boundaryShape = generatedShape->shapeBoundary
In reply to fxffxf:
Is there a way to test if a shape is static or dynamic?
I figured this part. Just didn't scroll down far enough in your reply. Also, what is the function to open the shape BOUNDARY class?
fxffxfFor dynamic shapes, you must open the dynamic shape (BOUNDARY class) not the generated shape (ETCH class).To obtain the boundary shape from a generate shape (assumes generatedShape is the Skill variable hold the shape dbid) boundaryShape = generatedShape->shapeBoundary
In reply to jwhend:
if you have a dbid of a shape the:
if dbid->shapeBoundary is nil then you can use dbid to open the shape
if dbid->shapeBoundary is non-nil then pass dbid->shapeBoundary to open the shape
If you finding shapes by using axlSetFindFilter method then you can add "BOUNDARY_SHAPES" to the list of items passed to the '?enabled' option and find will automatically promote a found shape to its owning dynamic shape.
Great! Works like a charm.