https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/en-USTelligent Community 13https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74705/fold-detection-values-for-optimization/1434942Tue, 06 Oct 2026 03:20:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:c6d3b38c-c35b-4a2c-99f4-1f3acc0f2684Simufact SupportThese fold detection surfaces can't be extracted. You can only see them in the GUI.https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74705/fold-detection-values-for-optimization/1434941Mon, 05 Oct 2026 13:52:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:fb70102e-ec74-4b14-a0f5-01741cbcf71casamRight now I'm using the fold detection option as mentioned in the picture. what is the best way of using the results in optimization?https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74705/fold-detection-values-for-optimization/1434933Thu, 01 Oct 2026 02:31:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:6b9adb88-bc2a-4d5b-8a34-b2c32e5fe3f4Simufact SupportHi Assam, to make sure I understand what exactly you are talking about. Are you using the fold detection option from the forming control or the possible fold results of the FV solver?https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74705/fold-detection-values-for-optimization/1434931Wed, 30 Sep 2026 15:37:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:9cf125cf-5761-4ef6-9246-cca79798935cMC202509189142Post moved from How to use the communityhttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74705/fold-detection-values-for-optimizationWed, 30 Sep 2026 09:50:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:273dd5f6-30ef-40dc-8413-959b943df342asamHow can i extract the fold detection data from simufact forming FVM process in terms of values so that I can use that data to train my optimization models. Do we have a python code for this?Pythonforminghttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufactTue, 29 Sep 2026 14:43:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:70e8b318-1882-4048-ab82-ca1499df626ahttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/Tue, 29 Sep 2026 14:43:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:b792e127-d536-4d12-8983-345a1e6ab781https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74335/how-can-i-add-a-cooling-period-between-layers-in-simufact-welding-2025/1432836Thu, 17 Sep 2026 11:41:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:acdb349a-b4af-451e-8f5c-109919bed5c2JLHi Kamar, you can use the termination criteria to stop a cooling load case when a specific temperature is reached. - Right click an your process. - Select "add termination criteria. - Use a setting like this: This will stop each cooling load case if the temperature drops below 300 °C or if the defined cooling time is reached. So it would be helpful to define a quite high cooling time between each layer in the robot settings. This termination criteria can also be used to stop the whole simulation, if the temperature drops below the threshold (i.e. 40 °C). For more information, please check the info sheet. Greetings, Julianhttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74335/how-can-i-add-a-cooling-period-between-layers-in-simufact-welding-2025Wed, 16 Sep 2026 13:21:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:624b6390-0de9-45b6-83fa-8e82cea012deKamar bouzgarouI am using DED/WAAM and I want to simulate: Layer 1 → cooling until 300 °C → Layer 2 → cooling until 300 °C → Layer 3. I cannot find how to add a cooling step between the deposition layers. Could someone explain how to do this in Simufact Welding 2025? kamar.Simufact Weldinghttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432824Thu, 20 Aug 2026 03:06:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:833773b6-972d-4b0d-90e1-b69d91060488QWHi Marek, Python script will only work for extracting the existing variables (and node coordinates) and doing the transformaion based on that. The transformed values can be used for further data processing outside Simufact. If they should be displayed as a new result value in Simufact, you are right that they have to be written in a new variable. But this is something that can only be achieved through Fortran subroutines. Qihttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432823Tue, 18 Aug 2026 03:39:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:1c65d20b-607a-4c07-93f9-9fbe1e04ace0Marek VindysHi Qi, However, I'm not sure how to write the transformed values into a new variable. Don't those Python scripts only work for displaying existing variables? I would also need to display just the Z coordinate, but Simufact only has displacements. Thanks! Marekhttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432817Mon, 17 Aug 2026 03:26:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:13062947-0fc3-4ec4-813f-6eedca3d4d64Marek VindysHi Qi, fine thanks, I'll try it in Python. Marekhttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432808Tue, 11 Aug 2026 09:47:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:cad20d26-89fb-4702-9058-eb79e949d936QWHi Marek, The transformation could be handled by a python script. Simufact provides the class Mesh to access the coordinates and results of each node: With these information and the definition of the new cylindrical coordinate system, you should be able to calculate the transformation. There could be existing libraries or functions like numpy for this purpose, but I'm not sure which one is the best choice. Creating user variables using subroutines in Fortran might also be feasible, but you will need to install a compiler for this and learn more about how the solver works internally. If you're interested, please have a look at the demo model "user-defined state and post variables" and the corresponding scientific tutorial. But overall, this should be more time-consuming compared to Python. Qihttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432807Fri, 07 Aug 2026 07:43:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:f489064f-bce9-4a61-b7cd-665b7a46f1b9Marek VindysHi QW, yeah, I figured it would be something like that. Can it be handled somehow in Python, or by creating a user variable in Fortran? Both look quite difficult. Thanks for the advice! Marekhttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432793Tue, 28 Jul 2026 05:44:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:5a163c9e-8454-4d61-a204-cc8fb4ac3484QWHi Marek, sorry for not being able to reply earlier. Now I believe I understand the problem better. I may have to correct my previous answer in some extent. The background/reason is that with the option "cylindrical coordinate system" transformation, there is actually no cylindrical tensor transformation in the mathematical sense applied to the result variables. Instead, all output result variables are transformed into a new Cartesian coordinate system with newly defined x, y, and z axes based on the settings specified in the " cylindrical coordinate system " dialog. In other words, the purpose of the "cylindrical coordinate system" transformation is only to translate and rotate the coordinate system so that the Z-axis coincides with the desired axis of rotation. This ensures that the predefined Radial and Tangential results remain meaningful (see the example below). During this process, the tensor components XX, YY, ZZ, XY, YZ and ZX are also transformed into the new coordinate system, but remain Cartesian. If the defined cylindrical axis is already aligned with the current Z-axis, no coordinate rotation is performed. As a result, all Cartesian tensor components remain unchanged. We don't output r–φ, φ–z, or z–r components in the cylindrical coordinate system at all. The workaround I can think of right now is extracting the coordinates and strain tensors in Cartesian coordinate system and performing the transformation via python. I also created a feature request to directly output the tensor components in cylindrical system but I cannot say when this will be implemented. I hope the situation is more clear now. Qihttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432788Thu, 23 Jul 2026 02:06:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:5e669970-d06b-41e9-a62f-6cb47b2bbc5cMarek VindysHi QW, Thank you for your reply. I'm not sure how to attach an image here. The Z-axis is the axis of the cylindrical coordinate system. The Tangential Total Strain and Radial Total Strain are transformed correctly, so I believe the cylindrical coordinate system is defined properly. However, the XY component of the strain tensor does not change at all after the transformation. It remains exactly the same as before the transformation. Marekhttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432786Wed, 22 Jul 2026 03:59:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:2b992804-c058-451f-b06f-f19f06c3ece0QWHi Merek, Basically you only have to do a result transformation by defining your cylindrical coordinate system, no other specific steps are required. But I have to double check the reason behind this. Could you please let me know how did you defined the cylindrical coordinate system, are you still using the z axis as cylindrical axis and (0,0,0) as origin? Does the problem occur when you change the definition? I will try to understand the problem with a small test model and get back to you. Qihttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432785Tue, 21 Jul 2026 02:35:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:811afa63-9664-4472-8ff5-947a62cea0e9Marek VindysHi Qi, Okay, but when I display the XY component of the strain tensor in the Cartesian coordinate system and then apply Result Transformation to the cylindrical coordinate system , the results do not change at all. So the displayed values still appear to be the XY component in the transformed local coordinate system, rather than the r–φ component of the strain tensor in the cylindrical coordinate system. Am I misunderstanding something, or is there another step required to obtain the cylindrical strain tensor components?https://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432784Mon, 20 Jul 2026 07:02:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:b0b9d9d6-d414-4ea3-bb52-15ad1df8eb06QWHi Marek, After applying a result transformation, not only the axial, radial and tangential strain results are recalculated. The components ( X, Y, Z, XY, YZ and ZX ) are transformed as well, although their labels remain unchanged. Therefore, these results should be interpreted in the transformed cylindrical coordinate system rather than in the original global Cartesian coordinate system. Qihttps://community.cadence.com/cadence_technology_forums/physical-system-simulation/simufact/f/simufact/74313/strain-tensor-in-cylindrical-coordinates/1432783Mon, 20 Jul 2026 05:37:00 GMT75bcbcf9-38a3-4e2e-b84b-26c8c46a9500:7b58fa56-8c15-40f9-aa10-38e788920cdaMarek VindysThanks for your reply. Okay, but which result is it? The XY component of the strain tensor remains the XY component ; it doesn't become the φr component .