How to calculate the length of a routing which is in different metal connected through via

Hi Amit and Bharath,

Although this is by no means a complete answer, the following SKILL code may assist you in finding path lengths.  It will be up to you to work in any layer changes, and associated overlaps, into the calculations. I wrote the code a while ago, so it will not cope with new OA objects such as pathSegs.


/* CCSgetPathLength.il

Group           Custom IC, Cadence Design Systems
Language        SKILL
Revision No.    1.2
Date Created    Jan 09, 2003
Last Modified
Tested in       IC446, IC50
Lint score      100 (best is 100)
Description:

A short procedure to use the currently selected path object and
sum the length of each of the segments and print the result in
the CIW.

If the user has infix turned on and nothing was selected already
then the current mouse location is used to select an object -
this assumes that the procedure is run when a bindkey is pressed.

***************************************************

SCCS Info: @(#) CCSgetPathLength.il 02/05/03.13:32:29 1.2

********************************************************************
* DISCLAIMER: The following code is provided for Cadence customers *
* to use at their own risk. The code may require modification to   *
* satisfy the requirements of any user. The code and any           *
* modifications to the code may not be compatible with current or  *
* future versions of Cadence products.                             *
* THE CODE IS PROVIDED "AS IS" AND WITH NO WARRANTIES, INCLUDING   *
* WITHOUT LIMITATION ANY EXPRESS WARRANTIES OR IMPLIED WARRANTIES  *
* OF MERCHANTABILITY OR FITNESS FOR A PARTICULAR USE.              *
********************************************************************

*/

/***************************************************************
*                                                              *
*                      CCSgetPathLength()                      *
* Uses the selected object, if no object is selected then the  *
* current mouse pointer location is used (if infix is on). If  *
*  the object is a path then iterate over the points and sum   *
*  the length of each segment (works for 45 degree segments).  *
*  Prints the summed length of the selected path in the CIW.   *
*                                                              *
***************************************************************/

procedure(CCSgetPathLength(@optional (obj car(geGetSelectedSet()))
                            silent )
  let((prevpt x y (length 0.0))

  ;; if no object is selected, and infix is turned on, then
  ;; use the current mouse location to select the object.
  ;; This is for use with a bindkey, i.e. it is set to run
  ;; this procedure when a key is pressed.

  unless(obj
    when(hiGetCIWindow()->infix
      geSelectPoint(nil enterPoint())
      obj = car(geGetSelectedSet())
    )
  )

  ;; when the selected object is a path object, iterate
  ;; over the list of points and sum the length. This
  ;; assumes orthogonal or 45 degree segments only.

  when(obj~>objType == "path"
    foreach(pt obj~>points

      ;; operate on pairs of points, if no previous point
      ;; then set it to be the same as the first and use
      ;; it in the next iteration.

      if(!prevpt then

        ;; initialise prevpt to be the first point

        prevpt=pt
      else

        ;; for simplicity keep the calculation the same
        ;; regardless of which direction the segment is
        ;; oriented. One of x or y will be 0 unless the
        ;; path segment is not horizontal or vertical.

        x=abs(car(pt) - car(prevpt))
        y=abs(cadr(pt)-cadr(prevpt))
        length = length + sqrt(expt(x 2) + expt(y 2))
        prevpt=pt
      )
    );; foreach
    ;; print the summed length to the CIW, length will
    ;; have a value as it was initialised as 0.0

    unless(silent
      printf("Path length: %5.2f\n" length)
    )

    ;; return the length calculated
    length
  );; when selected object is a path
  );; let
);; procedure CCSgetPathLength

I hope that this helps you,

Best regards,

Lawrence

Hi Amit and Bharath,

Although this is by no means a complete answer, the following SKILL code may assist you in finding path lengths.  It will be up to you to work in any layer changes, and associated overlaps, into the calculations. I wrote the code a while ago, so it will not cope with new OA objects such as pathSegs.


/* CCSgetPathLength.il

Group           Custom IC, Cadence Design Systems
Language        SKILL
Revision No.    1.2
Date Created    Jan 09, 2003
Last Modified
Tested in       IC446, IC50
Lint score      100 (best is 100)
Description:

A short procedure to use the currently selected path object and
sum the length of each of the segments and print the result in
the CIW.

If the user has infix turned on and nothing was selected already
then the current mouse location is used to select an object -
this assumes that the procedure is run when a bindkey is pressed.

***************************************************

SCCS Info: @(#) CCSgetPathLength.il 02/05/03.13:32:29 1.2

********************************************************************
* DISCLAIMER: The following code is provided for Cadence customers *
* to use at their own risk. The code may require modification to   *
* satisfy the requirements of any user. The code and any           *
* modifications to the code may not be compatible with current or  *
* future versions of Cadence products.                             *
* THE CODE IS PROVIDED "AS IS" AND WITH NO WARRANTIES, INCLUDING   *
* WITHOUT LIMITATION ANY EXPRESS WARRANTIES OR IMPLIED WARRANTIES  *
* OF MERCHANTABILITY OR FITNESS FOR A PARTICULAR USE.              *
********************************************************************

*/

/***************************************************************
*                                                              *
*                      CCSgetPathLength()                      *
* Uses the selected object, if no object is selected then the  *
* current mouse pointer location is used (if infix is on). If  *
*  the object is a path then iterate over the points and sum   *
*  the length of each segment (works for 45 degree segments).  *
*  Prints the summed length of the selected path in the CIW.   *
*                                                              *
***************************************************************/

procedure(CCSgetPathLength(@optional (obj car(geGetSelectedSet()))
                            silent )
  let((prevpt x y (length 0.0))

  ;; if no object is selected, and infix is turned on, then
  ;; use the current mouse location to select the object.
  ;; This is for use with a bindkey, i.e. it is set to run
  ;; this procedure when a key is pressed.

  unless(obj
    when(hiGetCIWindow()->infix
      geSelectPoint(nil enterPoint())
      obj = car(geGetSelectedSet())
    )
  )

  ;; when the selected object is a path object, iterate
  ;; over the list of points and sum the length. This
  ;; assumes orthogonal or 45 degree segments only.

  when(obj~>objType == "path"
    foreach(pt obj~>points

      ;; operate on pairs of points, if no previous point
      ;; then set it to be the same as the first and use
      ;; it in the next iteration.

      if(!prevpt then

        ;; initialise prevpt to be the first point

        prevpt=pt
      else

        ;; for simplicity keep the calculation the same
        ;; regardless of which direction the segment is
        ;; oriented. One of x or y will be 0 unless the
        ;; path segment is not horizontal or vertical.

        x=abs(car(pt) - car(prevpt))
        y=abs(cadr(pt)-cadr(prevpt))
        length = length + sqrt(expt(x 2) + expt(y 2))
        prevpt=pt
      )
    );; foreach
    ;; print the summed length to the CIW, length will
    ;; have a value as it was initialised as 0.0

    unless(silent
      printf("Path length: %5.2f\n" length)
    )

    ;; return the length calculated
    length
  );; when selected object is a path
  );; let
);; procedure CCSgetPathLength

I hope that this helps you,

Best regards,

Lawrence