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  3. How to calculate the length of a routing which is in different...

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How to calculate the length of a routing which is in different metal connected through via

AmitBiswas
AmitBiswas over 16 years ago
Hi, I am trying to find out the length of one routing by clicking at two points of that routing. Here the routing is in metal2 and metal3 connected through via23. Is there any way to check in SKILL that exactly where that metal is getting connected with other one through via. Consider that all are paths there is no rectangle or polygon. Is it possible to do it using only SKILL or I need to use Assura also.............? Thanks & Regards, Amit
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  • Andrew Beckett
    Andrew Beckett over 15 years ago

    Hi Bharath,

    There wasn't a picture, so I can't really see what your problem was. The begin and end offset arguments are for controlling the offset and the beginning and end of the path - i.e. in the direction of the path. As I said before, if you want to offset the path sideways, you need to use an offset subpath with the ?sep and ?width arguments.

    So without a picture, and without the code sample of what you actually tried, it's not possible to explain to you what to do, because your requirements are still unclear - I can only assume I've misunderstood your requirements, which is why the picture and code would help.

    Regards,

    Andrew

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  • Andrew Beckett
    Andrew Beckett over 15 years ago

    Hi Bharath,

    There wasn't a picture, so I can't really see what your problem was. The begin and end offset arguments are for controlling the offset and the beginning and end of the path - i.e. in the direction of the path. As I said before, if you want to offset the path sideways, you need to use an offset subpath with the ?sep and ?width arguments.

    So without a picture, and without the code sample of what you actually tried, it's not possible to explain to you what to do, because your requirements are still unclear - I can only assume I've misunderstood your requirements, which is why the picture and code would help.

    Regards,

    Andrew

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