For loop

You could use the SKILL++ do() function, or simply use a while loop:

i=0
while(i<20
  println(i)
  i=i+2
)

Or look at solution 11025352 on support.cadence.com - this is one I wrote on "Understanding SKILL macros". There's a macro on implementing a C-like for loop.

Regards,

Andrew.

Thanks a lot.

The note on the macro is quite useful for new users like me.

On a different subject, I'm wondering what's the best way to debug a SKILL code? I mean is there a tool which could be used for the editor. Right now I"m relying on the error messages I see in my CIW.

Adil.

Adil,

If using IC613/IC614 you have Tools->SKILL Development Environment (New) which is a GUI based tool which allows you to place breakpoints on lines in the code, trap errors, trace variables and so on.

You also have the older Tools->SKILL Development menu which brings up the toolbox which gives access to a debugger - again, it can intercept errors and put breakpoints at the beginning or end of functions.This is also in older releases.

For more info look in  <instdir>/doc/skhelp/skhelp.pdf and <instdir>/doc/skdevref/skdevref.pdf

Note that this is a licensed tool - it requires product 900 (SKILL Development Environment).

Regards,

Andrew.

Thanks once again for the info on the development tool - sounds very useful indeed. I checked the list of products we've currently & unfortunately this is not available.

Best regards,

Adil.

Andrew Beckett said:

Adil,

If using IC613/IC614 you have Tools->SKILL Development Environment (New) which is a GUI based tool which allows you to place breakpoints on lines in the code, trap errors, trace variables and so on.

You also have the older Tools->SKILL Development menu which brings up the toolbox which gives access to a debugger - again, it can intercept errors and put breakpoints at the beginning or end of functions.This is also in older releases.

For more info look in  <instdir>/doc/skhelp/skhelp.pdf and <instdir>/doc/skdevref/skdevref.pdf

Note that this is a licensed tool - it requires product 900 (SKILL Development Environment).

Regards,

Andrew.

I know this is a pretty old topic, but I was looking for exactly this and I think of this solution...

for( cnt -10 0

println( abs( cnt))

)

10

9

8

7

6

5

4

3

2

1

0