Select pins and pin label by SKILL.

 Hi Marbs

A layout pin must have a terminal and net name. So it will definitely have connectivity info in its properties form. Just to clarify the question, do you mean that you would like to select isolated layout pins that are not touching any other devices/interconnect?

Best regards
Quek

Yes sir, thats what I mean,

I want to select all isolated pins in the layout that are not touching any other devices,

by using skill.

Please help.

Regards,

Marbs

Hi Marbs

You can find the pins using the skillscript below. Save it as "findpins.il" in your working directory and load it in ciw using:

load "findpins.il"

Press F10 in a layout and note the output messages in ciw.

In general, you can start coding such a script using the following steps:
a. Identify the target. In this case, it is a pin
b. Identify unique properties on the target through ~> operator:
- Select the target in layout/schematic
- Enter a=car(geGetSelSet()) in ciw to get a handle to the target
- Use a~>? to know more about the target
c. After you have some idea on its properties, do some looping to get it
d. Make some guesses on the type of skill functions needed. E.g. we need to select the pins so we will need some selection functions
e. Refer to the appropriate manuals for the skill functions. E.g. for layout, look in sklayoutref.pdf
f. $CDSHOME/doc/skdfref/skdfref.pdf and $CDSHOME/doc/sklayoutref/sklayoutref.pdf are very useful manuals

Best regards
Quek

procedure( CCSfindPins()
   let( (cv allPins count overlapShapes)
      cv=geGetWindowCellView()
      allPins=setof(x cv~>shapes x~>pin)
      count=0
      foreach( pin allPins
         overlapShapes=dbGetOverlaps(cv pin~>bBox pin~>lpp 0:32)
         unless( length(overlapShapes)>1
            geSelectFig(pin)
            count++
            printf("Isolated %L pin with net %s found at %L\n"
                 pin~>lpp pin~>net~>name centerBox(pin~>bBox))
         ) ;unless
      ) ;foreach
      printf("%n isolated pin(s) selected in cell %s\n"
                                               count cv~>cellName)
   ) ;let
) ;procedure

hiSetBindKey("Layout" "F10" "CCSfindPins()")

Hi Sir,

Thank you very much for the skill code and the clear

skill coding instruction. 

Regards, 

Marbs

hi,

i have a script which modify a cell and save it as a different name in same library.

But its unable to change the label  (text).

Please help me with this.

Thanks & regards

ashutosh

ashutosh,

Try reading your post, with the assumption that the reader has no knowledge (other than what you typed) of what your problem is. In other words, they do not have access to the knowledge of the problem that resides in your head.

Do you think they'd be able to answer it?

Also, it probably would have made more sense for this to be a new topic, unless it is very closely related to the original question (it's unclear since you gave no details whatsoever).

Ask a vague question, and you'll either get a vague answer (or more likely no answer at all).

Regards,

Andrew.

Hi Andrew,

Thanks for the reply.

I will try to elaborate it. I am working on some standard cell library. Some cells has to be modified and saved with different cell name in same library. My skill script is copying the cell and after modification its saving it with different name as required.

for eg initial cell : muxprx1   new cell: muxprstx1

But in the modified cell(muxprstx1)  label is same as muxprx1.

so can you suggest me how to modify the label text using skill.

Regards

ashutosh

Assuming you have two variables, oldCellName and newCellName and a variable cv containing the cellView id, then something like the following would do it:

; in case you haven't already got the cellView open
; cv=dbOpenCellViewByType(libName newCellName viewName "" "a")
foreach(shape cv~>shapes
  when(shape~>objType=="label" && shape~>theLabel==oldCellName
    shape~>theLabel=newCellName
  )
)
dbSave(cv)

Again, bit of a wild guess because I don't know what form the label you've got actually is.

Regards,

Andrew.

Thanks a lot.

It wll be of great help.

Regards

ashutosh