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delete shape on the basis of coordinates

bloodwayn

hi

is there any way to delete a rectangle on the basis of the coordinates? so i know where the rectangle is but i can't find a function or so where i can say: delete the rectangle( or figure) on the position x,y (specially xMin,yMin xMax, yMax for rectangle).
so i wouldn't search the whole layout for all rectangles and compare the coordinates until i found the right one.

regards
philip

  • I'm no expert here but it seems like DJSelectAreaPlus() should do the job.  Example:

    \a DJSelectAreaPlus()
    \i 0:12250
    \a addPoint(hiGetCommandPoint())
    \i 2500:19950

    Regards, Zach

  • Hi Zach,

    That's not a Cadence function; I assume it's part of some customisation at your company. The way I'd do it is to use dbGetTrueOverlaps(cvId list(xy xy)) (where xy is the point you want), and then use dbDeleteObject() on the results. Or in a graphical environment you could do a selection (e.g. using a ge.*Select type function) and then delete the selected objects - but I'd go for a solution which works without needing the windows to be open to make it more flexible.

    Regards,

    Andrew.

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