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problem with sorting

Aritra

Hi,

   I want to sort some 2 points paths according to their x or y co-ordinates . The input to the procedure will be the database id of the paths and the outputs will also be the database id of the sorted paths. 

  The resulting operation will give me the paths from left to right or top to bottom. I am tring to use sort() function but I am unable to get the currect syntax for using it.

Please help me with it.

  • Slayer

    for example to sort by Y-coordinate if u need sort which pass upper the other:

     l_pathList = sort(l_pathList lambda((a b) cadadr(a~>bBox) > cadadr(b~>bBox)));

  • kb how

    I create a simple function to sort paths from left to right, this is only a scratch work, you may need to modify it to suit your request.

    procedure( sortPath( @key (pathIds geGetSelSet()))
     let(()
      sort( pathIds lambda((a b) lessp(leftEdge(a~>bBox) leftEdge(b~>bBox))))
     )
    )

    This will return the selected paths and sort it from left to right. You may try to sort it using the startPt or endPt rather than using bBox.

    -How- 

  • Aritra
    Hi,
        I have solved the problem by using the following line: 
    horz_path_list=sort(horz_path_list lambda((a b) yCoord(car(a~>points)) < yCoord(cadr(b~>points))))
        Thanks Slayer, how for the assist.

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