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  3. Bindkey info

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Bindkey info

psill
psill over 13 years ago

When I view my bindkey definitions of my session, I see an extra command that I did not define with hiSetBindKey.

What is the difference in the "Command" and "enterFunction Command"?

If a "enterCommand" is defined can it only be edited with the bindkey editor?

Last question, how do I define one and not the other?

 

Thanks 

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  • skillUser
    skillUser over 13 years ago

    Hi (Paul?),

    The enterFunction bindkey is active during an "enter function", that is, a function that accepts input such as when deleting objects, the command is accepting co-ordinates for the location of the object to delete, or when copying, the location of the object to copy and location of the new copy, and of course design entry commands such as when creating polygons, paths, rectangles etc.  This allows the user to define a different action when in one of the 'entry mode' commands.

    You can define a bindkey to be active during an enterFunction by appending "EF" to the key definition, here's an example from the documentation:

      hiSetBindKey("Schematics" "None <Btn1Down> EF"   "mouseAddPt( )")
     

     Hopefully this answers your questions.

    Regards,

    Lawrence.

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  • skillUser
    skillUser over 13 years ago

    Hi (Paul?),

    The enterFunction bindkey is active during an "enter function", that is, a function that accepts input such as when deleting objects, the command is accepting co-ordinates for the location of the object to delete, or when copying, the location of the object to copy and location of the new copy, and of course design entry commands such as when creating polygons, paths, rectangles etc.  This allows the user to define a different action when in one of the 'entry mode' commands.

    You can define a bindkey to be active during an enterFunction by appending "EF" to the key definition, here's an example from the documentation:

      hiSetBindKey("Schematics" "None <Btn1Down> EF"   "mouseAddPt( )")
     

     Hopefully this answers your questions.

    Regards,

    Lawrence.

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