SKILL code to generate lower routes with same path properties of the selected path

Hi Neeraj,

The trouble is that the for() function always returns t, whereas you want something that returns an appended list of the contents from each time you call it.

What I suggest you do is something like this:

; first build a list of numbers
listOfNums=nil
for(i 1 via_cont listOfNums=tconc(listOfNums i))
listOfNums=car(listOfNums)
; then transform the list of numbers into a concatenated list of
; subrect lists
foreach(mapcan i listOfNums
  list(
    list(
      ?layer ...
    )
    list(
      ?layer ...
      ?sep -(((via1_w/2)+via1_spc)*(i+1)
       ...
    )
  )
)

The idea is that the body of the foreach(mapcan ..) returns a list of your three subrect definitions, and these will be concatenated - so if via_cont was 3, you'd end up with a list of 9 subrect definitions. If the foreach(mapcan ...) is the last thing in the branch of the cond(), it will be the return value to the ?subRect

There's several ways of skinning this cat, but the above is relatively straightforward.

Regards,

Andrew.

Hi Neeraj,

The trouble is that the for() function always returns t, whereas you want something that returns an appended list of the contents from each time you call it.

What I suggest you do is something like this:

; first build a list of numbers
listOfNums=nil
for(i 1 via_cont listOfNums=tconc(listOfNums i))
listOfNums=car(listOfNums)
; then transform the list of numbers into a concatenated list of
; subrect lists
foreach(mapcan i listOfNums
  list(
    list(
      ?layer ...
    )
    list(
      ?layer ...
      ?sep -(((via1_w/2)+via1_spc)*(i+1)
       ...
    )
  )
)

The idea is that the body of the foreach(mapcan ..) returns a list of your three subrect definitions, and these will be concatenated - so if via_cont was 3, you'd end up with a list of 9 subrect definitions. If the foreach(mapcan ...) is the last thing in the branch of the cond(), it will be the return value to the ?subRect

There's several ways of skinning this cat, but the above is relatively straightforward.

Regards,

Andrew.