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Determine a point is inside of a polygon or outside...

Alvin Park

Hi.... This is KT PARK in Korea. 

Do you have any SKILL Command or code 

to determine a point is inside of a polygon or outside at Virtuoso Layout Suit?

 

 dbLayerInside or dbLayerOutside does not help.... T_T

Parents

  •  There is my small function, instead leIsPointInsideFig()u can use my function in no graph mode and modify:

     ;-; Arguments:   n_x    - x coord for cheking point
    ;-;         n_y    - y coord for cheking point
    ;-;         l_points - points of shape
    ;-;  
    ;-; Return value: list of points
    ;-;  
    ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
    procedure(IsPointInPolygon(n_x n_y l_points)
        let( (n b1 b2 b_flag xpi ypi i)
           
            n = length(l_points);
        xpi = declare(xpi[n+1]);
        ypi = declare(ypi[n+1]);

        ;create array with x and y points
        for(i 1 n-1   
           xpi[i] = car(nthelem(i l_points));
           ypi[i] = cadr(nthelem(i l_points));
        );end for
       
        xpi[0] = car(nthelem(n l_points));
        ypi[0] = cadr(nthelem(n l_points));
         
        i = 0;
        b_flag = nil;

        while(i <= n-2
             b1 = (n_y > ypi[i]);
             b2 = (n_y <= ypi[i+1]);
         
         if( !((b1 && !b2) || (b2 && !b1)) then
               if( n_x-xpi[i] < (n_y-ypi[i])*(xpi[i+1]-xpi[i])/(ypi[i+1]-ypi[i]) then
             ;dprint("a vot her znaet");
                 b_flag = !b_flag;
               )
             )
         i++;
        )
       
        b_flag;
          
        );end let
    );procedure.
     

Reply

  •  There is my small function, instead leIsPointInsideFig()u can use my function in no graph mode and modify:

     ;-; Arguments:   n_x    - x coord for cheking point
    ;-;         n_y    - y coord for cheking point
    ;-;         l_points - points of shape
    ;-;  
    ;-; Return value: list of points
    ;-;  
    ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
    procedure(IsPointInPolygon(n_x n_y l_points)
        let( (n b1 b2 b_flag xpi ypi i)
           
            n = length(l_points);
        xpi = declare(xpi[n+1]);
        ypi = declare(ypi[n+1]);

        ;create array with x and y points
        for(i 1 n-1   
           xpi[i] = car(nthelem(i l_points));
           ypi[i] = cadr(nthelem(i l_points));
        );end for
       
        xpi[0] = car(nthelem(n l_points));
        ypi[0] = cadr(nthelem(n l_points));
         
        i = 0;
        b_flag = nil;

        while(i <= n-2
             b1 = (n_y > ypi[i]);
             b2 = (n_y <= ypi[i+1]);
         
         if( !((b1 && !b2) || (b2 && !b1)) then
               if( n_x-xpi[i] < (n_y-ypi[i])*(xpi[i+1]-xpi[i])/(ypi[i+1]-ypi[i]) then
             ;dprint("a vot her znaet");
                 b_flag = !b_flag;
               )
             )
         i++;
        )
       
        b_flag;
          
        );end let
    );procedure.
     

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