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skill assoc : How does assoc command of skill work with anumerical value ?

Giora Karni
How does assoc command of skill work ?
 
After looking closely into several numerical examples, I got the following findings:
 a = '( ( 20n   xx xx) ( 40n yy yy) (50n zz zz) ) assoc( 2e-08 a)   returns:    (2e-08 xx xx) assoc( 4e-08 a)   returns:    (4e-08 yy yy) assoc( 5e-08 a)   returns:    nil  ß       ?????

but if I try:
a = '( ( 20e-09   xx xx) ( 40e-09 yy yy) (50e-09 zz zz) ) assoc( 2e-08 a)   returns:    (2e-08 xx xx) assoc( 4e-08 a)   returns:    (4e-08 yy yy)

assoc( 5e-08 a)   returns:    (5e-08 zz zz)  
 
I suspect that there is a numerical bug here. It looks like 5e-08 ≠ 50n . I noticed that for 20n,40n,80n,160n (power of 2) the problem doesn't appear.

virtuoso version ICADV12.1-64b 03/15/2013 18:29 (sjfnl166)

Giora Karni
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  • Giora Karni

    Hi Andrew,

    Thank you for a full explanation and solution.

    with regards,

    Giora

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  • Giora Karni

    Hi Andrew,

    Thank you for a full explanation and solution.

    with regards,

    Giora

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