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convertion of oldtech sechmatics to newtech schematics

siva 234

Hi Sir,

I have one technolgy schematics,in that having mos's(p&n mos) and all the components like caps &resistors ,So i want to replace that mos's of old technology to new another technology mos's .

if it is possible to convert with SKILL scrips are not please let me know

Thanks in adavance

venkatasiva.j

Parents
  • siva 234

    andrew , what iam saying is 

    I divided old technology schematics into two libraries 1.digital library 2. analog librarey

    digital library: 

    I want to change only old tech  width , old tech length is converted to new tech length(instance of new tech length like 40nm)

                     Eg: old tech    w=100n L=60n

                           new tech   w=x n  L=40n   ===>x=(w of old tech*(2/3))  keeping W/L constant in old &new technologies

    so finallay i want expression is

    old tech width * (2/3) =new tech width

    old tech length  =new tech length ( automatic change  instrance of new tech what ever you given code :procedure(fixIt1(inst parName val )
                                                                                                           printf("Fixing %s on %s\n" parName inst~>name)
                                                                                                             )

    analog library: I want to chane length and width.

    expresssions:

    new tech width = old tech width * (3/4)         

    new tech length=old tech length * (1/sqrt(2))

     

    Thanks for each quick replying of this issue.

     

    Thanks in advance,

    venkatasiva      

             

Reply
  • siva 234

    andrew , what iam saying is 

    I divided old technology schematics into two libraries 1.digital library 2. analog librarey

    digital library: 

    I want to change only old tech  width , old tech length is converted to new tech length(instance of new tech length like 40nm)

                     Eg: old tech    w=100n L=60n

                           new tech   w=x n  L=40n   ===>x=(w of old tech*(2/3))  keeping W/L constant in old &new technologies

    so finallay i want expression is

    old tech width * (2/3) =new tech width

    old tech length  =new tech length ( automatic change  instrance of new tech what ever you given code :procedure(fixIt1(inst parName val )
                                                                                                           printf("Fixing %s on %s\n" parName inst~>name)
                                                                                                             )

    analog library: I want to chane length and width.

    expresssions:

    new tech width = old tech width * (3/4)         

    new tech length=old tech length * (1/sqrt(2))

     

    Thanks for each quick replying of this issue.

     

    Thanks in advance,

    venkatasiva      

             

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