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Using Skill to Select Vias not fully enclosed by metal

Terry S

Is there a way to only select vias that cross a shape boundry?

I have a very large FET that has numerous Source and Drain Vias and the top level metal covering them now has to be slotted leaving a large amount of existing Vias to be manually deleted where the slots pass over them.

I can generate another layer that consists of simply the slots and then, if CDS OA 6.1.5 has the capability, then one could simply select only the Vias that touch the newly created shapes.

Is that possible to do in Skill?

Thanks

Terry 

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  • skillUser

    Hi Terry,

    Building on what Derek suggested (nice tip!), here is some more code around it.  Assume that the slot shapes have been selected and then stored in a list, in my example I used testShapes and 'lcv' is the layout cellview database object, then you can identify and delete the overlapped vias like this:

    
vias = apply('nconc foreach(mapcar shape testShapes dbViaQuery(lcv shape~>bBox )))
mapcar('dbDeleteObject vias)

    The first step build a "flat" list of the list-of-list shapes returned by the foreach-mapcar; the dbViaQuery might return more than one shape. Then map the function dbDeleteObject over this list to delete each via found.

    Hopefully this will answer your question?

    Regards,

    Lawrence.

Reply
  • skillUser

    Hi Terry,

    Building on what Derek suggested (nice tip!), here is some more code around it.  Assume that the slot shapes have been selected and then stored in a list, in my example I used testShapes and 'lcv' is the layout cellview database object, then you can identify and delete the overlapped vias like this:

    
vias = apply('nconc foreach(mapcar shape testShapes dbViaQuery(lcv shape~>bBox )))
mapcar('dbDeleteObject vias)

    The first step build a "flat" list of the list-of-list shapes returned by the foreach-mapcar; the dbViaQuery might return more than one shape. Then map the function dbDeleteObject over this list to delete each via found.

    Hopefully this will answer your question?

    Regards,

    Lawrence.

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