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How to find smallest element in a list

gharish
gharish over 11 years ago

 Hi,

Is there any function to find smallest or biggest number in a given list.

Ex: mylist = list( 1 2 3 4) 

I need smallest  number in mylist.

I have tried to use max() and min() functions. But not working.

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  • Andrew Beckett
    Andrew Beckett over 11 years ago

    Yes I belive it is, or rather it would be if I'd not made a silly mistake when I typed it in - I meant to do this but accidentally omitted the cdr in the argument to the foreach. So it should be:

    procedure(CCFoverList(func lst)
      let(((result car(lst)))
        foreach(elem cdr(lst) result=funcall(func result elem))
        result
      )
    )

    With the previous min/max examples, you'd not see the difference, but if you use CCFoverList('plus mylist) you'd see it double-counted the first element in the list.

    A lispy way of doing it would be to use recursion, but that will also have stack size limitation (maybe if you write it the right way and can use the tail call optimization option, but I didn't spend any time thinking about that - hardly worth it when it is so simple anyway).

    Regards,

    Andrew.

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  • Andrew Beckett
    Andrew Beckett over 11 years ago

    Yes I belive it is, or rather it would be if I'd not made a silly mistake when I typed it in - I meant to do this but accidentally omitted the cdr in the argument to the foreach. So it should be:

    procedure(CCFoverList(func lst)
      let(((result car(lst)))
        foreach(elem cdr(lst) result=funcall(func result elem))
        result
      )
    )

    With the previous min/max examples, you'd not see the difference, but if you use CCFoverList('plus mylist) you'd see it double-counted the first element in the list.

    A lispy way of doing it would be to use recursion, but that will also have stack size limitation (maybe if you write it the right way and can use the tail call optimization option, but I didn't spend any time thinking about that - hardly worth it when it is so simple anyway).

    Regards,

    Andrew.

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