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Acess array elements using plist

frasheed

 Hello,

 

I am wrting a SKILL code in which I am stuck at a point here I want to access the array element defined through plist:

EXAMPLE:

 setplist( 'B1 '( p 200 y list(1 2 3 4 5 6 ) )

IN = B1

; I want to access the value of y[0], I nam trying this

IN->y[0]

; but It's giving me error  *Error* arrayref: can't handle y[0]

 

Can anyone plese tell me where I am going wrong ?

 

Parents

  • The main problemis that lists are not arrays. They are linked-lists which are separate data types to arrays, and are sequential in nature. Generally speaking if you think of lists as arrays, you will make the mistake of assuming that they are random-access, when they are sequential, and write code that is inefficient. 

    Secondly, there are a number of mistakes in your example, so it can't work as is. The second single quote in the setplist will cause the list() not to be evaluated. So it should be:

    setplist('B1 list('p 200 'y list(1 2 3 4 5 6)))
    IN='B1

    Or:

    setplist('B1 `(p 200 y ,list(1 2 3 4 5 6)))  ; note the backquote and also comma before the bits you want to evaluate
    IN='B1

    Then you could use:

    nth(0 IN->y)

    Or, if you really want an array:

    setplist('B1 `(p 200 y ,listToVector(list(1 2 3 4 5 6))))
    IN='B1
    IN->y[0]

    I'm wondering if you really want to use a plist on a symbol either. Maybe some other data structure would be more appropriate - but depends on your application?

    For example - you could do:

    defstruct(MyStruct p y)
    IN=make_MyStruct(?p 200 ?y listToVector(list(1 2 3 4 5 6)))
    OUT=make_MyStruct(?p 100 ?y listToVector(list(7 8 9 10 11 12)))
    IN->y[3]
    OUT->y[3]

    Regards,

    Andrew.

Reply

  • The main problemis that lists are not arrays. They are linked-lists which are separate data types to arrays, and are sequential in nature. Generally speaking if you think of lists as arrays, you will make the mistake of assuming that they are random-access, when they are sequential, and write code that is inefficient. 

    Secondly, there are a number of mistakes in your example, so it can't work as is. The second single quote in the setplist will cause the list() not to be evaluated. So it should be:

    setplist('B1 list('p 200 'y list(1 2 3 4 5 6)))
    IN='B1

    Or:

    setplist('B1 `(p 200 y ,list(1 2 3 4 5 6)))  ; note the backquote and also comma before the bits you want to evaluate
    IN='B1

    Then you could use:

    nth(0 IN->y)

    Or, if you really want an array:

    setplist('B1 `(p 200 y ,listToVector(list(1 2 3 4 5 6))))
    IN='B1
    IN->y[0]

    I'm wondering if you really want to use a plist on a symbol either. Maybe some other data structure would be more appropriate - but depends on your application?

    For example - you could do:

    defstruct(MyStruct p y)
    IN=make_MyStruct(?p 200 ?y listToVector(list(1 2 3 4 5 6)))
    OUT=make_MyStruct(?p 100 ?y listToVector(list(7 8 9 10 11 12)))
    IN->y[3]
    OUT->y[3]

    Regards,

    Andrew.

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