How to get the tail of list .

What do you mean by tail here? Normally the tail of a list in SKILL is everything but the first entry. Given that the top level list is a list of a single sublist (which has six sublists), the tail would be nil. You'd normally find the tail of a list using cdr().

Perhaps if you can state what you're expecting the result to look like given the above example, it would help me (or anyone else) to know what you really want?

Thanks,

Andrew.

Hi Andrew,

Thank you very much for your reply.

I want to get the last pair of numbers in the list .

For example :

 X = (((-9.1 13.6)

        (-7.4 13.6)

        (-7.4 12.6)

        (-5.5 12.6)

        (-5.5 13.6)

        (-3.8 13.6)

    )
)

The output in the ciw should be (-3.8 13.6) .

Best Regards,

Marben

car(last(car(X)))

Hi Andrew,
This is exactly what I'm looking for.
Its car(last(cdr(X))), which returns the last pair of numbers in the list,  (-3.8 13.6) .
While car(last(car(X))), returns 13.6 .


Thank you very much.
Your reply is very helpful .


Best Regards,
Marben

Marben,

If using car(last(cdr(X))) gives you the right answer, then the list cannot look like what you said - it must have one fewer set of parentheses than you showed. Also, the cdr() would be unnecessary - it would be sufficient to do car(last(X)). So my expectation is that your list looks like this:

X='((-9.1 13.6)
        (-7.4 13.6)
        (-7.4 12.6)
        (-5.5 12.6)
        (-5.5 13.6)
        (-3.8 13.6)
    )

car(last(X)) => (-3.8 13.6)

If the list is as you showed, then it would definitely be car(last(car(X))) .

Kind Regards,

Andrew.