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"List name" decided by a variable

gaurc

I want to create a list whose name decided by a variable. i.e. :-

x~>libName_cs = list()

so when x~>libName = "Library1" ,    then     Library1_cs = list()

and when  x~>libName = "Library2" ,    then     Library2_cs = list()

How to do it?

  • You can, but you almost certainly shouldn't do this.

    set(concat(x~>libName "_cs") list(...))

    and then:

    symeval(concat(x~>libName "_cs")

    to retrieve the value. 

    However, far better would be to use a hash table:

    cs=makeTable('libraryLists nil) ; the first argument doesn't really matter what you use - doesn't have to be unique
    cs[x~>libName]=list(...)
    cs[y~>libName]=list(...)

    Andrew

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