Modify cdf param value based on its current value using SKILL

This is a very strange thing to want to do - it doesn't strike me as having any physical meaning - adding a 100n or 100u to a value depending on it's existing range sounds rather peculiar to me.

Anyway, using num=cdfParseFloatString(inst~>w), then using some conditional statements (e.g. if() or cond() to check the range the value is in) and then adding 100n or 100u to the result and cdfFormatFloatString() before setting it back seems straightforward enough (although unusual). I don't understand what you don't understand?

Regards,

Andrew.

Sorry andrew I might not have explained it clear enough. I am just trying to create a test case with different cdf values than that of default. so I am trying to create a non default test case to QA our LVS deck by changing some cdf parameter values.  Basically I just wanted to increase some of the cdf param value to create non default test case.  

So i have tried as following but getting some error. Having some problem with format of a value.

oldValue=cdfParseFloatString("200n") => 2e-07

newValue=oldValue+10n => 2.1e-07

cdfFormatFloatString(newValue "n") =>  *Error* cdfFormatFloatString: argument #1 should be a string (type template = "t") - 2.1e-07

sprintf(newValue "%L\n" newValue) => "2.1e-07\n"

cdfFormatFloatString(newValue "n") => nil

Seems like getting rid of \n at the end of the newValue will do the job.

So I used
pattern=pcreCompile("\n")
newValue=pcreReplace(pattern  newValue "" 0)

so final code will look like following to get "210n" from "200n"

oldValue=cdfParseFloatString("200n")

newValue=oldValue+10n

sprintf(newValue "%L\n" newValue)

pattern=pcreCompile("\n")

newValue=pcreReplace(pattern newValue "" 0)

cdfFormatFloatString(newValue "n")

thanks for your help Andrew. I appreciate it .