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confused about the apply() operation

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I am confused about the operation of the apply(), when applied on and().

As far as I know, the apply() works in a way, that the elements of the second list argument are bouned to the formal argumets of a function provided as a first argument and then the function is called.
If I try
    apply('and list(list(1 2)) )
I obtain the following error :
*Error* eval: not a function - 1
However when trying and(list(1 2)) (what should be IMHO the same), the result is :
(1 2)

OK, so it looks like the apply() function calls eval on each element of the second argument. However, when trying
apply('print list(list(1 2) ) )
I obtain
(1 2)
nil

, what means that the eval is not called by apply(). Can someone explain this?

Thanks,
Miro








Originally posted in cdnusers.org by miro
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    Hello Andrew,

    Thanks for the explanation. What made me confused was that nor Virtuoso Skill Functions Skill Quick Reference nor full skill reference mention that and is a syntax form, meanwhile e.g. in the case of foreach they do.
    Actually the full skill reference says about and() :

    Evaluates from left to right its arguments to see if the result is nil. As soon as an argument evaluates to nil, and returns nil without evaluating the rest of the arguments. Otherwise, and evaluates the next argument. If all arguments except for the last evaluate to non-nil, and returns the value of the last argument as the result of the function call. Prefix form of the && binary operator.

    what hints on the syntax form, but I thought that "evaluate" just means "look on" and not "call eval()".
    Once more, thanks.
    Miro


    Originally posted in cdnusers.org by miro
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  • archive

    Hello Andrew,

    Thanks for the explanation. What made me confused was that nor Virtuoso Skill Functions Skill Quick Reference nor full skill reference mention that and is a syntax form, meanwhile e.g. in the case of foreach they do.
    Actually the full skill reference says about and() :

    Evaluates from left to right its arguments to see if the result is nil. As soon as an argument evaluates to nil, and returns nil without evaluating the rest of the arguments. Otherwise, and evaluates the next argument. If all arguments except for the last evaluate to non-nil, and returns the value of the last argument as the result of the function call. Prefix form of the && binary operator.

    what hints on the syntax form, but I thought that "evaluate" just means "look on" and not "call eval()".
    Once more, thanks.
    Miro


    Originally posted in cdnusers.org by miro
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