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getting the dbID for an instance in the layout

Inas Mohammed

Hello,

I need to get the dbID for certain transistor in order to do some operations on it after that.

The idea is that i need to check for a transistor in a pattern, if this transistor is at lower left of upper right do some commands.

so i need to get value of x which then will be used as follows.

when(row=0 && col==0  lowerleft=x)

when(row=Rows-1 && col=Cols-1 upperright=x)

I thought about like trying to create instances again on the old one with the same names in these places using dbCreateInst just to have the ID, then use it.

But it doesn't work

So can you help me with this issue please.

thanks

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  • This still makes absolutely no sense. If you've generated the pattern (presumably the instances), don't you have the instance IDs then? Or are you saying that you know the instance names - in which case you could use dbFindAnyInstByName(cv name) to find the instance id of the named instance? Calling dbCreateInst if you already have the instances in existence makes no sense - it would try to create a new instance in the layout, and if the instance name already exists, it will fail because you can't have two instances with the same name.

    I'm still no clearer as to what you're doing. Maybe you should just talk to customer support so that you can actually show them rather than not being able to describe your problem well enough here (given that I'm answering this in a few minutes during my working day, I really don't have the time to go back and forth to tell you how to describe your problem in clearer language, or to magically guess what you're trying to do; sorry if that sounds harsh).

    Regards,

    Andrew.

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  • This still makes absolutely no sense. If you've generated the pattern (presumably the instances), don't you have the instance IDs then? Or are you saying that you know the instance names - in which case you could use dbFindAnyInstByName(cv name) to find the instance id of the named instance? Calling dbCreateInst if you already have the instances in existence makes no sense - it would try to create a new instance in the layout, and if the instance name already exists, it will fail because you can't have two instances with the same name.

    I'm still no clearer as to what you're doing. Maybe you should just talk to customer support so that you can actually show them rather than not being able to describe your problem well enough here (given that I'm answering this in a few minutes during my working day, I really don't have the time to go back and forth to tell you how to describe your problem in clearer language, or to magically guess what you're trying to do; sorry if that sounds harsh).

    Regards,

    Andrew.

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