Convert M1 bBox coordinates inside a hierarchy to upper hierarchy coordinates

OK, so if you have a single bBox you'd do:

  dbTransformBBox(bBox inst~>transform)

where inst was the instance id of the instance of the pcell. So I mean that inst is an instance in hierarchy X-1, and the shapes within it are in the coordinate system of hierarchy X (using your terminology).

To do it for your entire list, you'd do:

  B=foreach(mapcar bBox A dbTransformBBox(bBox inst~>transform)

that would give you a list of transformed bBoxes.

Hope that helps,

Regards,

Andrew

From Cadence Help, i found the usage of this function: dbTransformBBox() and it expects from me to give "l_list" argument l_list is the transform(displacement vector, rotation/reflection, and magnification(optional)).
But i dont know the transform, thats what i want to know, i want to know the bBox of the M1 coordinates in hierarchy(X-1), sorry if i am sounding dumb, i am new in SKILL.  

The transform is available on the instance in which the shape is placed. If your rectangle is placed inside an instance stored in variable inst1, then the transform of the shape is inst1~>transform. You'll notice that this transform simply consists of the xy of the instance and the orient of the instance and 1.0 for the magnification. You could therefore build the transform yourself with list(inst1~>xy inst1~>orient 1.0) although that is a waste of time. If a shape is multiple levels deep in the hierarchy, then you need to build the transform from the instances hierarchically. You can combine one or more transforms using dbConcatTransform.

Derek

The transform is available on the instance in which the shape is placed. If your rectangle is placed inside an instance stored in variable inst1, then the transform of the shape is inst1~>transform. You'll notice that this transform simply consists of the xy of the instance and the orient of the instance and 1.0 for the magnification. You could therefore build the transform yourself with list(inst1~>xy inst1~>orient 1.0) although that is a waste of time. If a shape is multiple levels deep in the hierarchy, then you need to build the transform from the instances hierarchically. You can combine one or more transforms using dbConcatTransform.

Derek

I am doing this: 
reqM1list=nil
foreach(element z
h=list(dbTransformBBox(element geGetSelSet()~>transform))
reqM1list=append(reqM1list h))
reqM1list

where reqM1list is the list of the converted coordinates/bBoxes of M1 shapes according to current hierarchy.   

It is throwing me this error: *Error* dbTransformBBox: Invalid transform - (((0.273 0.336) "R0" 1.0))

geGetSelSet() is the instance i have selected from click of the mouse in which shape M1's bBox i need to convert to current hierarchy. . 

I noticed that (0.273 0.336) is the xy of my instance. 

But i am not getting what i want. I want to convert M1 shapes's bBoxes inside this instance to be converted to my current level hierarchy bBoxes.  

Moreover, what is the l_list argument (the 2nd argument) in the documentation for the "dbTransformBBox" function. I know its a transform, but transform of what?- the M1 shape? or the insatnce in which the M1 shape is? 

The dbTransformBBox wants one transform. The one transform is a list that looks like this: ((0.273 0.336) "R0" 1.0)

The transform is a list of three items: xy, orient, magnification  (note also that xy is a list of two points). It is a transform of the instance and the shapes in the instance. If the shapes were at the top level, they would not have a transform or the transform would be ((0 0) "R0" 1.0). If the shapes are in an instance placed at 10, 5 with a rotation of R90, then the shapes will need to be transformed by that amount to know their top level position.

You are passing in a list of transforms because geGetSelectedSet returns a list of selected items. Therefore geGetSelSet()~>transform is a list of one transform. Notice the extra parentheses in the error message:  (((0.273 0.336) "R0" 1.0))

This would solve your current implementation:

h=list(dbTransformBBox(element car(geGetSelSet())~>transform))

As a tip, I almost always avoid append because of performance reasons with long lists. There is no reason for you to create h as a list and then append it to another list. You should use cons instead. The cons command will put the new item on the front of the list. If the order of the list matters, you can reverse the list when you are done.

reqM1list=nil
transform = car(geGetSelSet()~>transform)
foreach(element z
    reqM1list = cons(dbTransformBBox(element transform) reqM1list)
)
reqM1list

Thanks, that solved my problem! Thank you for your explanation, now i understand it.

In essence, my original reply explained this too - and used a foreach mapcar to build the list. That means the list is in the same order, without needing to repeatedly cons (and optionally reverse the list). Adapting my original reply:

  B=foreach(mapcar bBox A dbTransformBBox(bBox inst~>transform))

to your variables. it would be:

  transform=car(geGetSelSet())~>transform
  reqM1list=foreach(mapcar bBox z dbTransformBBox(bBox transform))

The foreach mapcar allows you to create a new list with 1-1 correspondence to the original list.

Regards,

Andrew.

Thanks Andrew so much! :)