How to convert a string to a list

Hi Anna,

Do you really want it as a list, perhaps you might want it as just a symbol?  Anyway, the following will do what you want:

theString = "A1"
list(stringToSymbol(theString)) => (A1)

By the way the backquote (`) has a special meaning and is different to the quote ('), normally one would use a single quote to obtain a literal without any evaluation (the backquote allows selective evaluation and so to avoid confusion I would limit its use to the cases where it is being used for that purpose).

Hopefully this will help you.

Best regards,

Lawrence.

Hi Lawrence,

Thanks! That will work.

You're right. I just mis-used the backquote (`), that should be quote (') to make it as a list.

I just have another question on how I could concatenate the list in a single list?

For example, I have this list of symbols that is being generated in a loop.

In another procedure, I need it to be like this:

list('(A1) '(A2) '(B1) '(B24) '(C1) '(C2))

I want to know how I could store the result in each loop, then concatenate all in a single list.

Thanks,

Anna

Hi Anna,

Several ways:

listOfBumps=nil
foreach(loopVar ...
  bumpList=list(stringToSymbol(...))
  listOfBumps=cons(bumpList listOfBumps)
)

The list will be in reverse order. You could reverse it using the reverse() function at the end if the order matters (or don't bother if the order is irrelevant). You could use tconc to construct the list in order, but that's a bit more complicated (not very, but I don't want to confuse you).

If the list you are processing has a one to one correspondence with the output list (i.e. you are dealing with a list of something that you're processing, and every single one has a "bump" list), then:

listOfBumps=foreach(mapcar loopVar ...
  ... do whatever you need to ...
  ; final thing in loop is what gets added into resulting list
  list(stringToSymbol(...))
)

This is all a bit of a guess, because you didn't give much info as to what your loop is doing.

Regards,

Andrew