access the value of Annotation

The simplest would be to use the write parameter on the dc  analysis to write to a file - this will save a file (by default in the netlist directory unless you give a full path) with node-voltage pairs.

Andrew.

Thank you Andrew, could you tell me where is the info in the document, I looked for it for a while, but I couldn't find it. Or could you give me a simple?

Not entirely sure what you're asking, but to do this is pretty easy. On the dc analysis form, click on the Options and then fill in an appropriate name for the write parameter (the default that ADE uses is "spectre.dc" and as that's a local name, it will be saved in the netlist directory):

Then after running the simulation, if your'e unsure where to find the file, use the right mouse button over the Cadence logo in the ADE L window (there's a similar choice for ADE Explorer; for ADE Assembler/XL you can right mouse over a result point and Open Terminal):

Then having done that, there's a toolbar showing you where the results are - click on the terminal icon:

If in that terminal (since you're in the psf directory), you can do "cd ../netlist" and then "more spectre.dc" (or use your favourite editor) and it will show something like this (I didn't show the entire file):

# CHECKPOINT_VERSION 1
# Generated by spectre (mode: Spectre) from circuit file `input.scs' during analysis dcOp.
# 11:02:53 AM, Sat Jun 20, 2020
# Number of equations = 200
# The default unit is V, otherwise its unit is after #unit
E0:p	-8.60570632466539e-17   #unit A
E5:p	0   #unit A
E6:p	0   #unit A
E7:p	0   #unit A
E8:p	0   #unit A
I21:outn_inref_flow	1.36713191543474e-06   #unit A
I21:outp_inref_flow	1.36713191543474e-06   #unit A
I21:vos_flow	0   #unit A
ibias	0.339545202246329
inn	0.986330832272234
inp	0.986326529419071
NVCM	1
net024	0.849615489302179
net039	0.986328680845653
net043	0.986328680845653
net049	-4.3028531623327e-06
net056	0.986328680845653
net057	0.849615489302179
net069	-0
net072	0.986328680845653
net077	3
OUTN	0.849615510816444
OUTP	0.849615467787913
outdiff	4.3028531623327e-08
V0:p	-0.00970361330891634   #unit A
V6:p	0   #unit A
vcm:p	-3.08134721903946e-34   #unit A
vdd!	2.90296386691084
vddx!	0

Hope that helps.

Andrew

this is exactly what i want, thanks.   

by the way, in the file you showed, 

"V0:p	-0.00970361330891634   #unit A" 


can you tell me what does the "p" stand for ? 

this is exactly what i want, thanks.   

by the way, in the file you showed, 

"V0:p	-0.00970361330891634   #unit A" 


can you tell me what does the "p" stand for ? 

The "p" is the name of the terminal on the voltage source, and the value is the current flowing through that terminal.

Andrew.

Thank you