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help with branch decision on layout heirarchy and DbConcatTransform

malcolm70

Hi Cadence - 

need help with layout heirarchy.  I have a layout cell where I have bunch of labels, and I am using dbGetOverlaps() for locating the underneath rectangle.

I'm using cadence 18. 

My current flow is something like:

labelgroup=selectedSet()

foreach(label labelgroup

   overlapShape=dbGetOverlaps(cvID label~>bBox layerUnderneath 3)  ; look 3 levels down

  ) ; foreach

step1=dbConcatTransform(car(list) car(cadr(list))

step2 =dbConcatTransform(step1 car(cadr(cadr(list))))

shapePoints=dbTransformBBox(shape~>bBox step2)

the problem is "SOMETIMES" the shape I want isn't 3 levels down, it's actually 2 levels down.

The return list is *USUALLY* something like (db:xxxxxxx  (db:xxxxx (dbxxxx dbxxxx)))  the final pair is of course the rectangle and it's instance location

The problem is that I have *TWO* hardcoded concatTransform statements and then transformBBOX.

When the heirarchy level is 2 the second time I call concattransform I should be calling dbTransformBBox() and so the loop crashes. 

I can't figure out , I need some sort of test for the structure (dbxxxx dbxxxx)  , perhaps can I put concat transform in a while loop to check the list

length to find out  if that rectangle db id  is still down only one level.   Thanks in advance.  Malcolm  

Parents
  • Andrew Beckett

    Hi Malcolm,

    I think you probably just need to use dbGetHierPathTransform to get the overall transformation from the overlap list, and abGetHierShape from this post to get the shape itself. That post also shows using dbGetHierPathTransform.

    Does that help?

    Andrew

Reply
  • Andrew Beckett

    Hi Malcolm,

    I think you probably just need to use dbGetHierPathTransform to get the overall transformation from the overlap list, and abGetHierShape from this post to get the shape itself. That post also shows using dbGetHierPathTransform.

    Does that help?

    Andrew

Children
  • malcolm70
    in reply to Andrew Beckett

    Hi Andrew - thanks for the idea - I have success with the 3rd level down coordinate transform , but the defun abGetHeirPathShape gives an error.

    I loaded in the defun as this:

    (defun abGetHierPathShape (overlaps)
    (if (listp overlaps)
    (abGetHierPathShape (cadr overlaps))
    overlaps))

    then one at a time I added these lines :

    cv=geGetEditCellView()
    label=css()
    overlaps=dbGetTrueOverlaps(cv label~>bBox layer~>lpp 3 t)  ; layer is particular to my pdk...
    shape=abGetHierPathShape(overlaps)

    error message on CIW is :

    *Error* abGetHierPathShape: Runtime stack overflow caused by too deep recursion. Decrease the call stack level.
    <<< Stack Trace >>>
    abGetHierPathShape(cadr(overlaps))
    if(listp(overlaps) abGetHierPathShape(cadr(overlaps)) overlaps)
    abGetHierPathShape(cadr(overlaps))
    if(listp(overlaps) abGetHierPathShape(cadr(overlaps)) overlaps)
    abGetHierPathShape(cadr(overlaps))
    if(listp(overlaps) abGetHierPathShape(cadr(overlaps)) overlaps)
    ...

    If I use the statement : shape=cadr(car(reverse(car(overlaps))))  

    that seems to get the database key id for the shape, just wondering how to use the defun you mentioned.

    please advise, thank you.

  • Andrew Beckett
    in reply to malcolm70

    Malcolm,

    The issue is that dbGetTrueOverlaps/dbGetOverlaps returns a list of overlaps, each of which is a list. So you would need to loop over the result of dbGetTrueOverlaps to deal with each individual match. If there was only one, then you could do:

    shape=abGetHierPathShape(car(overlaps))

    Or you would do something (as in the post I referenced earlier) like this:

    foreach(overlap overlaps
      shape=abGetHierPathShape(overlap)
      transform=dbGetHierPathTransform(overlap)
      printf("transformed bbox is %L\n" dbTransformBBox(shape~>bBox transform))
    )

    You changed the argument name in the implementation of abGetHierPathShape, which doesn't affect anything, but confuses the meaning - in the original code the argument was called "overlap" which expressed better that it was dealing with a single overlap.

    Regards,

    Andrew.

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