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getting a list by ignoring few elements which are in another list?

Hi Team,

I have list list1=("n1" "n2" "n3" ) and list2=("w1" "n1" "w2" "n2" "w3"). By ignoring the elements in list1 i want to get list2=("w1" "w2" "w3") using SKILL.

Generally i am writing a foreach loop to compare list2 with list1. Is there any other alternate way to compare in 1 command?

Thanks

Lakshman

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Andrew Beckett over 3 years ago

Hi Lakshman,

If the lists are short, then using:

list3=setof(elem list2 !member(elem list1))

will do what you want. For very long lists you would consider using a hash table for doing the member lookup as this would be much more efficient:

list1Table=makeTable('memberTable nil)
foreach(elem list1 list1Table[elem]=t)
list3= setof(elem list2 !list1Table[elem])

Regards,

Andrew
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LakshmanQual over 3 years ago in reply to Andrew Beckett

Thanks Andrew!!
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LakshmanQual over 3 years ago in reply to Andrew Beckett

Thanks Andrew!!
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