How to get the filename from the filepath

There you go:

(defun cst_basename (path "t")
  "Equivalent to Unix basename"
  (let ((base (rindex path "/")))
    (if base (substring base 2) path)))

Cheers

Aurélien

Thanks Aurel...
Apart from this is there another way using skill commands (parse string , cdr)?

That is using SKILL commands. You just want yet another way? Not sure why you can't just use Aurélien's suggestion...

baseName=car(last(parseString(path "/")))

or:

basePat=pcreCompile("[^/]*$")
baseName=pcreExecute(basePat path) && pcreSubstitute(basePat "\\0")

There are of course many ways of doing this.

Andrew

Not sure this is the right place to mention that but if you go with Andrew's second solution, please be careful with pcreSubstitute as it relies on rexMagic switch

AurelBuche said:

Not sure this is the right place to mention that but if you go with Andrew's second solution, please be careful with pcreSubstitute as it relies on rexMagic switch

That's not good. I hadn't realised that and it's poorly documented. I think that's rather dangerous (I dislike global switches with a passion). I'll take that up with R&D...

Andrew