Skill code For designing layout for five different metal layers vias arranged in both X and Y axis.

Hi,

I'am not exactly sure what you mean with "use five different metals in both direction" but maybe you can share you code for the single metal layers so as I better understand what you want to achieve...

Max

Hi,

I'am not exactly sure what you mean with "use five different metals in both direction" but maybe you can share you code for the single metal layers so as I better understand what you want to achieve...

Max

rc = rodFillBBoxWithRects(
?cvId cv
?layer "M1"
?fillBBox list( 1:1 12:6 )
?width 2.0
?length 1.0
?gap "minimum"
?spaceX 0.7
?spaceY 0.7
?returnBoolean t
) ; end rodFillBBoxWithRects

Here i am using just one metal layer but how can change the layers to 4 different layers like M1, M2, LB, LV for each boxes following a certain distance of 500nm and dimension of each metal box should be .1*.1

oh I see - you are using rodFillBBoxWithRects(). Well rodFillBBoxWithRects() doesn't provide that functionality. So in a second step you'd have to iterate over all (only just created...) rectangles and then change the layers to whatever you like. Identifying these rectangles would be easy - you can assign a user defined property to them in rodFillBBoxWithRects() with the keyword argument ?prop, for example ?prop list("myProp" t):
(setof shape cv->shapes shape->myProp)

Moreover make sure you iterate over the rectangles in the right order - row by row and column by column. For example you could sort the rectangles by the coordinates of the lower left point of their bounding boxes.
(sort (setof shape cv->shapes shape->myProp)
   (lambda (s1 s2)
      (let  ( (x1 (xCoord (car s1->bBox)))
               (x2 (xCoord (car s2->bBox)))
               (y1 (yCoord (car s1->bBox)))
               (y2 (yCoord (car s2->bBox))))
         (cond
            (y1==y2
               (if x1<=x2 t nil))
            (y1<=y2 t nil)))))

Since I don't know what rows/cols should you want on which layer I cannot provide the remaining code which is essentially a loop that iterates over the list returned by the above sort() function.

Max

Hey Max: Thank you for the response. I want  M1, M2 , M3, M4 ,M5  in one ROW  following by 500nm distance  in both rows and columns. I want 3 row and 5 columns. 

shapes = (sort (setof shape cv->shapes shape->myProp)
   (lambda (s1 s2)
      (let  ( (x1 (xCoord (car s1->bBox)))
               (x2 (xCoord (car s2->bBox)))
               (y1 (yCoord (car s1->bBox)))
               (y2 (yCoord (car s2->bBox))))
         (cond
            (y1==y2
               (if x1<=x2 t nil))
            (y1<=y2 t nil)))))

(while shapes
   (foreach layerName '("M1" "M2" "M3" "M4" "M5))
      shape=(car shapes)
      shape->layerName = layerName
      shapes = (cdr shapes)))

The above code works only under the condition that you have in fact 3 rows and 5 columns - so it is up to you to take care of this in the rodFillBBoxWithRects(..) function.

Thank you