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Clip function to snip spectrum

Sjrg

Hi - I tried using clip function to snip spectrum between a range. Unfortunately it creates 2 additional frequency spurs, right at the min and max point of the range.

Suppose I'm clipping the spectrum from 400 MHz to 1GHz. The clipped spectrum introduces  frequency spurs at 400 MHz and 1 GHz. In reality there are no frequency spurs at 400 MHz or 1 GHz in the unclipped waveform.

How do I get around this issue? Am I missing something?

Thanks

Ganesh.

Parents
  • henker

    You may add '?interpolate nil' to the arguments of the clip function (or set the interpolate field to 'no' in the clip form if you use the form. The default is yes.). When interpolating, new values are generated at the specified borders from neighbouring points in case that the new border do not coincide with actual data points. From your description, this seems to happen.

    Also check the help, this behaviour is actually explained.

    Regards,

  • Sjrg
    in reply to henker

    I don't see the interpolate argument in the calculator. Can you provide an example of how this interpolation can be turned off by an example formula.

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  • Sjrg
    in reply to henker

    I don't see the interpolate argument in the calculator. Can you provide an example of how this interpolation can be turned off by an example formula.

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  • Andrew Beckett
    in reply to Sjrg

    You must be using an old version. The ?interpolate argument was added in IC618/ICADVM20.1 ISR19, so if you are using an older version that that, it won’t appear. It certainly does in the expression builder in IC23.1 ISR 16 (I checked)..

    This is also covered in my article https://support.cadence.com/apex/ArticleAttachmentPortal?id=a1O3w000009mIrzEAE&pageName=ArticleContent

    although that doesn’t list the version it was introduced in.

    Andrew

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