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is string a number or not

Ejlersen

Hi

I've been searching for a funtion to check if a string is a number or not.

stringsamples could be

data="8FLASH"

data="8"

data="8.1"

atoi will return 8 for all of the above, atof will return 8.0 for them all

Anyone know a function to test this?

Best regards

Ole

 

  • djhutchi
    > procedure( test(arg) if(rexMatchp("^[0-9]*[.]*[0-9]+$" arg) then printf("%s is a number\n" arg) else printf("%s is not a number\n" arg)))

    function test redefined

    test

    > test( "0.2")

    0.2 is a number

    t

    > test("2.0")

    2.0 is a number

    t

    > test( "8")

    8 is a number

    t

    > test("8FLASH")

    8FLASH is not a number

    t

    >
  • eDave
    Hi Ole, There must be a better way but this might help you: defun( StrNumberType (str, "t") when(str != "-" && substring(str, 1, 1) == "-", str = substring(str, 2)) unless(forall(pattern, '("^[0-9]+$", "^[0-9]*.[0-9]+$", "^[0-9]+.[0-9]+e[0-9]+$", "^[0-9]+.[0-9]+e-[0-9]+$"), !rexMatchp(pattern, str)) type(readstring(str)) ) ) Regards, Dave
  • eDave

    Let's try that in ie instead of Chrome:

    defun( StrNumberType (str, "t")
     when(str != "-" && substring(str, 1, 1) == "-", str = substring(str, 2))
     unless(forall(pattern, '("^[0-9]+$", "^[0-9]*.[0-9]+$", "^[0-9]+.[0-9]+e[0-9]+$", "^[0-9]+.[0-9]+e-[0-9]+$"), !rexMatchp(pattern, str))
      type(readstring(str))
     )
    )

  • Ejlersen

    Hi Dave

    Looks much better and thanks very much for the answer, although it was down the same road I was looking.

    There's also numberp, but converting a single element string to a symbol does not seem to work well.

    Best regards

    Ole

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