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Getting file name from a port

Hi,

Is there any function for getting the file name of a port?

Say if I want to get the “test.xls” from the below port.

inPort = infile(“C:\test\test.xls”)

Thanks,

Pawan

eDave over 12 years ago

get_filename(inPort)
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Tyler over 12 years ago

You can use get_filename(<port>) to get the full path for the port as a string. This can be passed to axlDMFileParts() to get the different portions, such as the directory, file name, file name with extension, or just file extension. Since you seem to want the file with extension, you would want the third element in the list returned from axlDMFileParts().
Regards,
- Tyler
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Pawandeep over 12 years ago

Hi Tyler/Dave,

Below works very well.

axlDMFileParts(get_filename(inPort))

Thanks,

Pawan
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