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What Is Returned from dbid->pins->startEnd

MarkGorecki

My code:

symDbidList = setof(symDbid axlDBGetDesign()->symbols symDbid->component->class == "DISCRETE")

;For each symbol dbid in the list, get X, Y,ref des, rotation, and comp name
smdOutput = outfile("./POD_SMD_Table.txt" "w")
foreach( symDbid symDbidList
symLoc = symDbid->xy
symLocX = car(symLoc)
symLocY = cadr(symLoc)
symRefDes = symDbid->refdes
symRot = symDbid->rotation
symName = symDbid->name
pinObj = (car (symDbid->pins))
pinLayer = pinObj->startEnd

pinLayer = ("CONDUCTOR/L06" "CONDUCTOR/L06")

I used:

layTxt1 = ( nthelem 1 pinLayer) which gave me "CONDUCTOR/L06"

I want to get the "L06" part of what looks like a string, but parsing using "/" doesn't work, and neither does substring.

Can someone please tell me how to get the "L06" portion from layTxt1?

Thanks

  • JuanCR
    +1

    Since pinLayer is a string, you can use the following command to get the "L06" substring from it: 

    strpbrk( pinLayer "L"); which is the same as strpbrk( "CONDUCTOR/L06" "L")

  • MarkGorecki
    0 in reply to JuanCR

    Hi Juan, thank you very much, that worked!  I don't understand why substring didn't work, but I'm going to use your suggestion.

  • B Bruekers
    0

    Parsestring splits the string in a list of strings. Since you are interested in the 2nd part of the string use cadr().

    cadr(parseString("CONDUCTOR/L06" "/"))  -> "L06"

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