Stats

  • Locked Locked
  • Replies 13
  • Subscribers 146
  • Views 20045
  • Members are here 0
This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

Changing amount of rows and columns in a selected contact cell

blankman

Hi all, Im trying to add bind keys to increment and decrement the amount of rows and columns in a selected contact cell.

 

Im using...

procedure(BSchangeVia2x1()
foreach(fig geGetSelSet()
  when(fig~>objType=="inst"
      propValue = car(fig~>prop~>value)
      fig~>prop~>value=propValue+1
    )
    )
)
hiSetBindKey("Layout" "Alt<key>KP_Add" "BSchangeVia2x1()")

 

However this increments both row and column values. Is there a way to increment only the row value and leave the column value as is?

Cheers,

Brian.

Parents

  • Brian,
    Take a look at the prop~>name values. You are incrementing every property by one. Since there are both row and column properties, you will therefore increment both. It is also possible that there are other properties that are not integers and will cause your code to fail. You can actually increment the value of the row and column settings by directly accessing the property by name.

    fig~>row =  fig~>row + 1  (assuming row is the property name)

    Also, in your code you are getting the prop value using:

    car(fig~>prop~>value)

    You are using "car" because fig~>prop is a list and therfore fig~>prop~>value is a list. However, you are incrementing ALL props with this since fig~>prop is a list:

    fig~>prop~>value = propValue + 1

    If you just want to change the first prop:

    car(fig~>prop~>value) = propValue + 1

    This is more consistent with the way you retrieved the value in the first place. However, the property list is not always going to be in the order you expect. You should look at the property name before you adjust the value either by going to the known property directly as I demonstrated (fig~>row), or by checking the name like this:

    foreach(prop fig~>prop
      when(fig~>prop~>name=="row"
        fig~>prop~>value = fig~>prop~>value + 1
      )
    )

    Derek

Reply

  • Brian,
    Take a look at the prop~>name values. You are incrementing every property by one. Since there are both row and column properties, you will therefore increment both. It is also possible that there are other properties that are not integers and will cause your code to fail. You can actually increment the value of the row and column settings by directly accessing the property by name.

    fig~>row =  fig~>row + 1  (assuming row is the property name)

    Also, in your code you are getting the prop value using:

    car(fig~>prop~>value)

    You are using "car" because fig~>prop is a list and therfore fig~>prop~>value is a list. However, you are incrementing ALL props with this since fig~>prop is a list:

    fig~>prop~>value = propValue + 1

    If you just want to change the first prop:

    car(fig~>prop~>value) = propValue + 1

    This is more consistent with the way you retrieved the value in the first place. However, the property list is not always going to be in the order you expect. You should look at the property name before you adjust the value either by going to the known property directly as I demonstrated (fig~>row), or by checking the name like this:

    foreach(prop fig~>prop
      when(fig~>prop~>name=="row"
        fig~>prop~>value = fig~>prop~>value + 1
      )
    )

    Derek

Children
No Data

Community Guidelines

The Cadence Design Communities support Cadence users and technologists interacting to exchange ideas, news, technical information, and best practices to solve problems and get the most from Cadence technology. The community is open to everyone, and to provide the most value, we require participants to follow our Community Guidelines that facilitate a quality exchange of ideas and information. By accessing, contributing, using or downloading any materials from the site, you agree to be bound by the full Community Guidelines.