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  3. Cadence5, output pane, subtraction of two signals

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Cadence5, output pane, subtraction of two signals

StreamCX
StreamCX over 15 years ago

How to view subtraction or sum (or some math operation) of two signals in ADE output pane? 

[URL=http://img23.imageshack.us/i/12dufferen.png/][IMG]img23.imageshack.us/.../URL]

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  • Quek
    Quek over 15 years ago

    Hi StreamCX

    If you are refering to using a previous measurement in another measurement, this is only possible in IC614. E.g.

    In output panel of IC614, we can have the following:

    sigA : VT("ABC")
    sigB : VT("XYZ")
    sigC : sigA - sigB

    If your "output pane" is actually refering to the waveform viewer wavescan (since this is what is shown in your picture), you can do it as follows:
    a. Open up calculator
    b. Click on the "wave" radio button
    c. Select the 2 signals in wavescan
    d. Press "-" or "+" in calculator
    e. Press plot button

    Hope that this helps you. : )

    Best regards
    Quek

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  • StreamCX
    StreamCX over 15 years ago

    Quek, thanks.

     I don`t know how to select 2 signals. I selecte one and write code,



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  • Andrew Beckett
    Andrew Beckett over 15 years ago

    Such expressions can be built easily in any version of Virtuoso. You don't have to have the dependent expressions support that Quek mentioned (which is in IC614).

    Do these steps in ADE:

    1. Outputs->Setup
    2. Hit the "Open" button to open the calculator
    3. On the tran tab, select vt.
    4. Click on one node on the schematic, then the other
    5. Hit the "-" button in the calculator. The buffer should show something like VT("/outp")-VT("/outn") (depending on the nets you've chosen)
    6. In the Setting Outputs form, hit the "Get Expression" button.
    7. Fill in the Name field (if you like) to something you find meaningful (e.g. "diff")
    8. Hit the Add button
    9. Cancel the Setting Outputs form.

    Now when you run the simulation,  the difference will be plotted automatically at the end.

    Regards,


    Andrew.

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