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Connecting multiple bits to same output bus in cadence schematic

roy83
Hi, I am building a digital system where i have to pass a bit of input-bus directly to the output bus, but cadence schematic composer gives an error when i try to do that. Error: Shorted terminals - memTerms "IN" & "A" thru signal "IN". Error: Shorted terminals - memTerms "A" & "IN" thru signal "IN". Is there a way to resolve this error . Thanks in Advance.

  • Hi Roy,

    I think that you will want to use the "cds_thru" component from the "basic" library, or perhaps a patchcord from the Create -> Patchcord menu (at least in IC61x that's where it is). 

    Hopefully this will help you.

    Regards,

    Lawrence.

  • hi, I tried the Create-> Patchcord option I tried to connect the Input bit IN[7] through a Pathcord to A[3] I get the following error. Shorted terminals - memTerms 'A[3]' & 'IN[7]' thru signals 'A[3]' & 'IN[7]' Regards, Roy

  • Hi Roy,

    Then I think that the cds_thru is the way to go since it is a component with different net names either side.  The documentation explains how the component is mapped for the different netlisters, for example in spectre the component is netlisted as an iprobe which does not add any complexity to the circuit (i.e. as opposed to a zero ohm resistor, say).  Try out the cds_thru if you can.

    regards,

    Lawrence.

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