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  3. make it clearly beta and betaeff

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make it clearly beta and betaeff

imagesensor123
imagesensor123 over 13 years ago

 Hi,

    these days i am doing some circuit simulation, and i got confused by beta and betaeff? according to the simple hand calculation equation id=1/2uCoxW/L(Vgs-Vth)^2 or id=1/2beta(Vgs-Vth)^2  or the others. and after simultion, i use the result->print->operation point and i found a betaeff parameter, i think it shold be same with beta, but after calculation id, i found the id(betaeff) is just a half of the id(beta), and how do you calculate the drain current id in saturation region?

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  • Andrew Beckett
    Andrew Beckett over 13 years ago

    Zfeng,

    As I said, most likely the problem is that you're using a basic text book equation, which does not represent what happens in bsim3v3 (or real life) for modern small geometry devices. You're effectively using a 30 year old model equation which was probably OK for large geometry processes.

    I have not tried to follow through the bsim3v3 equations to see if it can be simplified to the form you have above - that's a lot of work (and not especially useful).

    Regards,

    Andrew.

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  • Andrew Beckett
    Andrew Beckett over 13 years ago

    Zfeng,

    As I said, most likely the problem is that you're using a basic text book equation, which does not represent what happens in bsim3v3 (or real life) for modern small geometry devices. You're effectively using a 30 year old model equation which was probably OK for large geometry processes.

    I have not tried to follow through the bsim3v3 equations to see if it can be simplified to the form you have above - that's a lot of work (and not especially useful).

    Regards,

    Andrew.

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