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make it clearly beta and betaeff

imagesensor123

 Hi,

    these days i am doing some circuit simulation, and i got confused by beta and betaeff? according to the simple hand calculation equation id=1/2uCoxW/L(Vgs-Vth)^2 or id=1/2beta(Vgs-Vth)^2  or the others. and after simultion, i use the result->print->operation point and i found a betaeff parameter, i think it shold be same with beta, but after calculation id, i found the id(betaeff) is just a half of the id(beta), and how do you calculate the drain current id in saturation region?

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  • Quek

    Hi Zfeng

    Yes, usually hand calculations using your 1st order equation is good for estimation.

    Best regards
    Quek

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  • Quek

    Hi Zfeng

    Yes, usually hand calculations using your 1st order equation is good for estimation.

    Best regards
    Quek

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