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  3. Help me to interpret the waveform window.

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Help me to interpret the waveform window.

Muffassir
Muffassir over 13 years ago

 Hi all ,

Here is the attached image ..
[url=http://images.elektroda.net/30_1323332090.jpg][img]images.elektroda.net/.../url]

I want to know two things...

1)What i want to know is the interpretation in words of the Oval mark in the image.
Like :this is the signal at the value of this...is there any variable..

2)On x-axis the signal which we sweeep in the dc analysis form appears and the output is on the Y axis.The signal which i am sweeping in the Parametric analysis is the signal whose waveform gets drawn...Is this always the case..Correct my above statement if its wrong...Or it all depends on the signals which i choose to be plotted in the outputs(ADE L)

 

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  • Andrew Beckett
    Andrew Beckett over 13 years ago

    First of all, as outlined in the Forum Guidelines, please write carefully and clearly and do not use instant messaging shorthand (such as "u" for "you" and "wht" for "what" etc). I know I have the benefit of English being my first language (as I'm English), but even so, it makes it very hard to read.

    Secondly you are posting several separate threads with no links between them despite them all essentially being the same problem. So I'm assuming you're referring to this post? It's not clear in this current thread that the picture you're asking about was not produced by you, but is from the paper (I guess?). 

    The legend I am talking about is at the top of the graph with the details of what was plotting. In the graph that shows suffixes of <0>, <1>,<2> etc I suspect that the plot was done by setting the Iin2 current to each current in turn, running a single simulation, and then plotting the expression IS("/Vout1/PLUS")-IS("Vout2/PLUS") from the calculator. Because there were multiple waveforms with exactly the same name, that version of the waveform tool just added a unique identifier on the end - and the labelling was probably done manually. However, this is pure guesswork - I have no idea how these graphs were actually generated.

    In your graph, you appear to have got the current through the pin of your source somehow and it's ended up using spectre's internal name for the terminal (see "spectre -h isource" from the UNIX command line and you will see that the first pin of an isource is called "sink"). I don't know how you plotted this. Because you did a parametric sweep, it is doing the right thing and annotating the graph with the value of the sweep variable for each curve.

    I do not know what you are referring to with 'I3="-3n";/I2/MINUS' . Think carefully when you post - you are clearly assuming I am sitting on your shoulder and can see everything you can, which obviously I can't.

    I cannot explain why your circuit is not working. I have not seen your circuit, nor your simulation setup. It's like saying "here's a picture of a car I like, and here's what the fuel efficiency is reported as; I've built my own car that looks like this, but it won't start. Why?". Diagnosing something that could have numerous causes is rather hard.

    I'm guessing that you're probably a University student, so you are probably best advised to speak to your supervisor/lecturer to get some help from somebody who can see the details of what you're actually doing.

    I'm trying to be as helpful as possible here, but you must bear in mind that people on the forum can't read minds! 

    Best Regards, and good luck,

    Andrew.

     

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  • Andrew Beckett
    Andrew Beckett over 13 years ago

    First of all, as outlined in the Forum Guidelines, please write carefully and clearly and do not use instant messaging shorthand (such as "u" for "you" and "wht" for "what" etc). I know I have the benefit of English being my first language (as I'm English), but even so, it makes it very hard to read.

    Secondly you are posting several separate threads with no links between them despite them all essentially being the same problem. So I'm assuming you're referring to this post? It's not clear in this current thread that the picture you're asking about was not produced by you, but is from the paper (I guess?). 

    The legend I am talking about is at the top of the graph with the details of what was plotting. In the graph that shows suffixes of <0>, <1>,<2> etc I suspect that the plot was done by setting the Iin2 current to each current in turn, running a single simulation, and then plotting the expression IS("/Vout1/PLUS")-IS("Vout2/PLUS") from the calculator. Because there were multiple waveforms with exactly the same name, that version of the waveform tool just added a unique identifier on the end - and the labelling was probably done manually. However, this is pure guesswork - I have no idea how these graphs were actually generated.

    In your graph, you appear to have got the current through the pin of your source somehow and it's ended up using spectre's internal name for the terminal (see "spectre -h isource" from the UNIX command line and you will see that the first pin of an isource is called "sink"). I don't know how you plotted this. Because you did a parametric sweep, it is doing the right thing and annotating the graph with the value of the sweep variable for each curve.

    I do not know what you are referring to with 'I3="-3n";/I2/MINUS' . Think carefully when you post - you are clearly assuming I am sitting on your shoulder and can see everything you can, which obviously I can't.

    I cannot explain why your circuit is not working. I have not seen your circuit, nor your simulation setup. It's like saying "here's a picture of a car I like, and here's what the fuel efficiency is reported as; I've built my own car that looks like this, but it won't start. Why?". Diagnosing something that could have numerous causes is rather hard.

    I'm guessing that you're probably a University student, so you are probably best advised to speak to your supervisor/lecturer to get some help from somebody who can see the details of what you're actually doing.

    I'm trying to be as helpful as possible here, but you must bear in mind that people on the forum can't read minds! 

    Best Regards, and good luck,

    Andrew.

     

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