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How to Find the drawn net("MET1" "drawing") in the layout.

ShrikantTI
Requirement is that I need to find if there are any existing nets or paths in the layout so that I can connect the rest except those paths. Another issue is that when i draw the path the skill command does not recognize it as net until there net expression is given unlike in schematic it takes a predefined value. I tried to explore using shapes but did not have much definitive solution. Please can you help? Also how to find which all terminals is the path or net connected? I need to get the name of the terminals from the subblock as the terminals of the subblocks are not visible. Thanks, Shrikant
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  •  Hi Shrikant,

    I agree with Andrew that your questions are not clear, however I will try to provide some information that may help you.

    If you are designing in Virtuoso Layout Suite L (VLS-L, or perhaps you are using the older version of the tools, in which case it is named Virtuoso Layout Editor, or VLE) then connectivity is not automatically added to shapes, except perhaps for pins (terminals).  Any shape can be checked for connectivity, look for a "net" attribute on the shape, if it is 'nil' then there is no connectivity for that shape.  For example, let's assume that I selected a path (or pathSeg) in the layout, then I could check connectivity using SKILL:

    
  car(geGetSelectedSet())~>net
  => db:0x1652d512

     If you are looking for connectivity awareness in the tool then your best bet is to use the XL level of the product (VLS-XL in IC61x naming, or the older VXL if using IC5141).  When you use VLS-XL you can start from a connectivity reference like a schematic and generate the layout devices and their connectivity very easily - then when you hook up these devices the tool can aid you in highlighting connected pins on devices, and various other productivity enhancing features.  In either L or XL tiers you can add connectivity to a shape like a path by selecting it, pressing 'q' or Edit->Basic->Properties to open a form that allows you to modify the Connectivity.  In VXL or VLS-XL you can show/hide incomplete nets, so you can easily spot if any connection is missing.

    Hopefully this will help you. As Andrew said though, a more precise question (with information like version number, it's important, which is why we ask for it!) will likely yield a more helpful response.

    Regards,

    Lawrence.

Reply

  •  Hi Shrikant,

    I agree with Andrew that your questions are not clear, however I will try to provide some information that may help you.

    If you are designing in Virtuoso Layout Suite L (VLS-L, or perhaps you are using the older version of the tools, in which case it is named Virtuoso Layout Editor, or VLE) then connectivity is not automatically added to shapes, except perhaps for pins (terminals).  Any shape can be checked for connectivity, look for a "net" attribute on the shape, if it is 'nil' then there is no connectivity for that shape.  For example, let's assume that I selected a path (or pathSeg) in the layout, then I could check connectivity using SKILL:

    
  car(geGetSelectedSet())~>net
  => db:0x1652d512

     If you are looking for connectivity awareness in the tool then your best bet is to use the XL level of the product (VLS-XL in IC61x naming, or the older VXL if using IC5141).  When you use VLS-XL you can start from a connectivity reference like a schematic and generate the layout devices and their connectivity very easily - then when you hook up these devices the tool can aid you in highlighting connected pins on devices, and various other productivity enhancing features.  In either L or XL tiers you can add connectivity to a shape like a path by selecting it, pressing 'q' or Edit->Basic->Properties to open a form that allows you to modify the Connectivity.  In VXL or VLS-XL you can show/hide incomplete nets, so you can easily spot if any connection is missing.

    Hopefully this will help you. As Andrew said though, a more precise question (with information like version number, it's important, which is why we ask for it!) will likely yield a more helpful response.

    Regards,

    Lawrence.

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