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inquiry about the results of the serial capacitors in cadence

IanX

hello. everyone. I am doing the simulation in Cadence(IC6.1.6). Pls see the schematic below. What I want to know is the voltage of each capacitor. In each two circuit,  a 10V vdc , 2u cap and 8u cap. 1Ω resistor are used.  Tran simulation is used by setting 100u. I set initial volatge of all capacitor equal to 0.

After runing the simulation, the c1 always equals to 5V no matter what the value of the two capacitor are in the upper circuit. If I leave the initial voltage of the capacitor blank, the C1 equal to 0V

In the lower circuit, the C2t and C1b equals to 3.5V when 2 resistors are included. 

And by calculation the C1 should be 2V, and the the same with c2t. I don't know why the results are so strange. I have disucessed with many people. but I still could not fix it. Could someone help me? 

 

Parents
  • Hello, Andrew. Thank you so much! It works. But when I try to search 'rforce' to get more information in the virtuoso analog design environment L user guide, I found nothing. I'm not quite understand how 'rforce' works in the Cadence. Is it something like add a serial resistor in each node when the initial voltage in each node is calculated.
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  • Hello, Andrew. Thank you so much! It works. But when I try to search 'rforce' to get more information in the virtuoso analog design environment L user guide, I found nothing. I'm not quite understand how 'rforce' works in the Cadence. Is it something like add a serial resistor in each node when the initial voltage in each node is calculated.
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