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  3. Delay calculation for full adder circuit

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Delay calculation for full adder circuit

KISHORE085
KISHORE085 over 11 years ago

Hi all,

i've designed a full adder circuit in cadence virtuoso. i wanted to know how to calculate over all delay. i know how to calculate delay between two signals using calculator tool. But dont know to calculate over all delay. Please help.. . 

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  • Andrew Beckett
    Andrew Beckett over 11 years ago

    Please help explain what you mean by "over all delay". I don't understand your question, since you already know how to calculate delay between two signals. What's the difference in what you're asking?

    Kind Regards,

    Andrew.

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  • KISHORE085
    KISHORE085 over 11 years ago
    I mean the total time taken by the circuit to give output after providing input..
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  • KISHORE085
    KISHORE085 over 11 years ago
    hi, "over all delay" I mean the total time taken by the circuit to give output after providing input.
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  • Andrew Beckett
    Andrew Beckett over 11 years ago

    So why can't you use the delay function to do that?

    Regards,

    Andrew.

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  • KISHORE085
    KISHORE085 over 11 years ago
    Using delay function, it is possible to calculate delay between any two signals. But in my circuit, i have 3inputs and 2outputs. How to do in this? If i had 1input and 1output i could've calculated using delay function.
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  • Andrew Beckett
    Andrew Beckett over 11 years ago

    This of course depends on how you are varying the inputs. If the input stimuli is under your control, then you know when it changes and so you probably don't even need to use the delay() function. You could use the cross function to look for a crossing event in a particular window of the input or output. Then the "overall delay" would be:

    max(crossOut1 crossOut2)-min(crossIn1 crossIn2 crossIn3)

    where each cross above is a cross expression on that output or input.

    Something like that.

    Regards,

    Andrew.

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  • KISHORE085
    KISHORE085 over 11 years ago
    ok sir. Thanks a lot for replying. I'll check the cross function and get back to you.. Thanks again..
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