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connect all the bus lines together

Clidre

Hello,

I have a 10b bus, that I named out<0:1023>. I would like to connect all the lines together in one node and then connect the node to the top plate of a capacitor. If I connect directly  out<0:1023> to the capacitor, I have an error, of course. What can I do? Thanks

  •  Dear Clidre,

     

    > I have a 10b bus, that I named out<0:1023>.

     Would a 10 bit bus be denoted as out<9:0>?

    > I would like to connect all the lines together in one node and then connect the node to the top plate of a capacitor.

     I can think of two possible means to prevent a schematic error. I am sure many others will have good or better suggestions. Both are shown in the attached schematic.

    1.  Break the capacitor up into 1024 capacitors and connect the bus outputs to the top of each respective capacitor (see top schematic in figure)

    2. Encapsulate your signal source in a symbol view and connect all 1024 outputs together and to the top of your single capacitor (see lower schematic in figure). A warning is generated since all the outputs of the symbol pin are connected together, but there are no errors.

    Perhaps these suggestions might be appealing to you.

    Shawn

  • Thanks! I understood the option no2, but I'm not sure about option no1: if I connect each line to a single capacitance, it doesn't mean that all the capacitances are in parallel, because each bus line is independent from the others. I'll use the second option, anyway. I thought there was a more elegant solution without any warning, but it's ok! Better than errors :) Thank you so much!

  •  Dear Clidre,

     > I'll use the second option, anyway.

    Great - I am glad it helped and I understood your question. If you dislike the warning, you can set Virtuoso to ignore it using the  Options->Check->Rules Setup which will present you with a check box for the warning related to outputs shorted. If the warning irritates you, you can uncheck this box.

    Shawn

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