• Skip to main content
  • Skip to search
  • Skip to footer
Cadence Home
  • This search text may be transcribed, used, stored, or accessed by our third-party service providers per our Cookie Policy and Privacy Policy.

  1. Community Forums
  2. Custom IC Design
  3. Why gm is not zero even when iDS is a constant DC current...

Stats

  • Locked Locked
  • Replies 9
  • Subscribers 126
  • Views 17877
  • Members are here 0
This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

Why gm is not zero even when iDS is a constant DC current?

BaaB
BaaB over 9 years ago

I am trying to plot transconductance gm of M0 in the picture below. However, what I am supprised here is why gm is not zero when iDS is a constant DC current (1uA).

gm = diDS/dvGS

So according to this, gm should be zero when iDS is a constant.

As seen from the picture below, gm is not zero.

Could anyone explain why and how gm is calculated by the simulator?

Thank you.

  • Cancel
Parents
  • BaaB
    BaaB over 9 years ago

    Could you help me with this if you know about this and when you have time?

    From b4ld.c file of latest BSIM4 version this is the code section for calculating gm:

    Ids = Idsa * T0;  

    Gm = T0 * dIdsa_dVg - Idsa * (dVdseff_dVg + T9 * dVASCBE_dVg) / VASCBE;
    Gds = T0 * dIdsa_dVd + Idsa * (1.0 - dVdseff_dVd - T9 * dVASCBE_dVd) / VASCBE;
    Gmb = T0 * dIdsa_dVb - Idsa* (dVdseff_dVb + T9 * dVASCBE_dVb) / VASCBE;


    tmp1 = Gds + Gm * dVgsteff_dVd;
    tmp2 = Gmb + Gm * dVgsteff_dVb;
    tmp3 = Gm;

    Gm = (Ids * dVdseff_dVg + Vdseff * tmp3) * dVgsteff_dVg;

    The first yellow line is Gm that is equal to derivative of Ids with respect to Vgs. I already checked and understood how to derive this result.

    However, I couldn't follow why Gm is calculated as the second yellow line?

    Where does this equation come from?

    Also, if I am not mistaken the dimensions are inconsistent here.

    The left hand side of the equation Gm has unit of current over voltage while the right hand side has unit of current.

     

    • Cancel
    • Vote Up 0 Vote Down
    • Cancel
Reply
  • BaaB
    BaaB over 9 years ago

    Could you help me with this if you know about this and when you have time?

    From b4ld.c file of latest BSIM4 version this is the code section for calculating gm:

    Ids = Idsa * T0;  

    Gm = T0 * dIdsa_dVg - Idsa * (dVdseff_dVg + T9 * dVASCBE_dVg) / VASCBE;
    Gds = T0 * dIdsa_dVd + Idsa * (1.0 - dVdseff_dVd - T9 * dVASCBE_dVd) / VASCBE;
    Gmb = T0 * dIdsa_dVb - Idsa* (dVdseff_dVb + T9 * dVASCBE_dVb) / VASCBE;


    tmp1 = Gds + Gm * dVgsteff_dVd;
    tmp2 = Gmb + Gm * dVgsteff_dVb;
    tmp3 = Gm;

    Gm = (Ids * dVdseff_dVg + Vdseff * tmp3) * dVgsteff_dVg;

    The first yellow line is Gm that is equal to derivative of Ids with respect to Vgs. I already checked and understood how to derive this result.

    However, I couldn't follow why Gm is calculated as the second yellow line?

    Where does this equation come from?

    Also, if I am not mistaken the dimensions are inconsistent here.

    The left hand side of the equation Gm has unit of current over voltage while the right hand side has unit of current.

     

    • Cancel
    • Vote Up 0 Vote Down
    • Cancel
Children
No Data

Community Guidelines

The Cadence Design Communities support Cadence users and technologists interacting to exchange ideas, news, technical information, and best practices to solve problems and get the most from Cadence technology. The community is open to everyone, and to provide the most value, we require participants to follow our Community Guidelines that facilitate a quality exchange of ideas and information. By accessing, contributing, using or downloading any materials from the site, you agree to be bound by the full Community Guidelines.

© 2025 Cadence Design Systems, Inc. All Rights Reserved.

  • Terms of Use
  • Privacy
  • Cookie Policy
  • US Trademarks
  • Do Not Sell or Share My Personal Information