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  3. SPECTRE SP analysis -- noise correlation matrix

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SPECTRE SP analysis -- noise correlation matrix

Yevgeny
Yevgeny over 6 years ago

Good day.

I am running the following simple simulation (spectre 17.1.0): 

rx (xx yy) resistor r=50
port11 (xx vssa) port r=50 isnoisy=no
port12 (yy vssa) port r=50 isnoisy=no
sp sp ports=[port11 port12] start=100M stop=1G dec=80 \
    donoise=yes file="res.s2p"  datafmt=spectre paramtype=s noisedata=cy annotate=status

This is a 50Ohm resistor, connected between two 50 Ohm noiseless ports. When I look at the resulting file "res.s2p" I see the S-parameter noise correlation matrix: 

0.023      -0.023

-0.023      0.023

I would like very much to understand how this matrix defined in SPECTRE, since I fail to arrive at these numbers no matter how I try to define the matrix.

The S matrix itself is, by the way, perfectly sound:

1/3 2/3

2/3 1/3

 

I also tried to use "paramtype=y" (i.e. Y params instead of S params), the noise correlation matrix becomes:

0.02    -0.02

-0.02   0.02

which makes perfect sense (Y-param noise correlation, i.e. 1/R, if I divide by 4kT df). 

I apologize ahead if this is some stupid numerical error on my behalf; have spent quite some time on this, and could find nothing in docs. I filed cadence support request, but perhaps knowledgeable folk will answer faster Slight smile

Help is much needed. 

Thanks!

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  • Yevgeny
    Yevgeny over 6 years ago

    UPD: I continue working on this. I run SP analysis on a real circuit (quite complex, transistors, inductors, using Intel proprietary modes through CMI, and such). 

    I run it once with "paramtype=y noisedata=cy" and the second time with "paramtype=s noisedata=cy". I look at noise correlation matrix (CY) and discover something disturbing: 

    with "paramtype=s" I get non-negative eigenvalues, but with "paramtype=y" I get both positive and negative eigenvalues. The negative ones are large; can not be attributed to floating-point arithmetic errors. 

    To make my point clear: Correlation matrix is supposed to be positive semidefinite, and since it is Hermitian by construction, it should have had only non-negative eigenvalues. I have to conclude that the matrix provided by "paramtype=y" is broken!

    So far, one good thing has come out of it: I have refreshed some undergrad algebra. 

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  • Andrew Beckett
    Andrew Beckett over 6 years ago in reply to Yevgeny

    I would suggest you provide this info to the AE dealing with your case rather than posting it here. I'm not going to duplicate work done by a colleague (I don't have the time, for a start), so I suggest you follow up via the official channel. 

    Andrew.

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