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Plotting a Graph in cadence with different axis variables DC-Analysis Design variable

mirtaji65

I implemented a cascade current mirror circuit as shown blow.

And I want to plot the output voltage Vout  relative to the changes of input current (0<Iref<800uA) . I use DC-Analysis>Design-variable>start=0 / stop=800u then run the simulation
x-axis of chart in term of voltage and y-axis of chart in term of Iref

how can I change x-axis=Iref and y-axis=Vout 

Like the figure below

Parents

  • OK, first of all you're using a really old version (must be at IC6.1.4 or before). The last fix version of that came out more than 9 years ago. The waveform tool has changed considerably since then, and it's much easier in current versions.

    Luckily I still have access to IC6.1.4 so could go back and try this out. I initially thought you might need a custom calculator function to do this, but assuming you want it the opposite way to what you described (your plot already  shows the output voltage relative to the changes of input current), and then you're asking to make the x-axis iref and y-axis vout (which it already is). The figure below has current on the y-axis and voltage on the x-axis.

    Anyway, using the calculator, plot VS("/out") (hit the "vs" button and click on the out node, then press the "evaluate the buffer" icon to the right of the "clip" checkbox. Then use the "xval" function in the calculator on the same expression - xval(VS("/out")) and plot that too. Now right click over the x-axis on the graph, and pick "Edit". On that form, you can change the plot vs to the VS("/out") and then you should get the current versus the voltage (the xval plot would have given you the current values on the y-axis).

    Andrew

Reply

  • OK, first of all you're using a really old version (must be at IC6.1.4 or before). The last fix version of that came out more than 9 years ago. The waveform tool has changed considerably since then, and it's much easier in current versions.

    Luckily I still have access to IC6.1.4 so could go back and try this out. I initially thought you might need a custom calculator function to do this, but assuming you want it the opposite way to what you described (your plot already  shows the output voltage relative to the changes of input current), and then you're asking to make the x-axis iref and y-axis vout (which it already is). The figure below has current on the y-axis and voltage on the x-axis.

    Anyway, using the calculator, plot VS("/out") (hit the "vs" button and click on the out node, then press the "evaluate the buffer" icon to the right of the "clip" checkbox. Then use the "xval" function in the calculator on the same expression - xval(VS("/out")) and plot that too. Now right click over the x-axis on the graph, and pick "Edit". On that form, you can change the plot vs to the VS("/out") and then you should get the current versus the voltage (the xval plot would have given you the current values on the y-axis).

    Andrew

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