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Where can I find the meaning of each parameter of the DC operating point?

zuiying

I am learning cadence virtuosuo recently. I installed a tsmc0.18um process library. When performing simulations, it is often necessary to print dc operating points.

LIke this：（Q2 is a npn of tsmc0.18um process library ）

Where can I find the specific meaning of all these parameters? (I tried to use the help function that comes with cadence virtuoso to search. Some parameters can be found, but some don’t. For example, I didn’t find the explanation for ro in the figure above)

Thank you so much.

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  • Andrew Beckett

    Without seeing the models, I'm guessing that the model uses the "bjt" device in Spectre. If you run (from the UNIX command line): spectre -h bjt

    then scroll to the Operating Point Parameters section, you'll find:

    17 ro (Ohm) Common-emitter output resistance.

    as well as the other parameters. Info can also be found in the Spectre Circuit Simulator Components and Device Models Reference manual, near the end of the chapter.

    Andrew

Reply
  • Andrew Beckett

    Without seeing the models, I'm guessing that the model uses the "bjt" device in Spectre. If you run (from the UNIX command line): spectre -h bjt

    then scroll to the Operating Point Parameters section, you'll find:

    17 ro (Ohm) Common-emitter output resistance.

    as well as the other parameters. Info can also be found in the Spectre Circuit Simulator Components and Device Models Reference manual, near the end of the chapter.

    Andrew

Children
  • zuiying
    in reply to Andrew Beckett

    I am using spectre interactive in cadence virtuoso. It seems that there is no "spectre" command.

    But I find Info in the Spectre Circuit Simulator Components and Device Models Reference manual. Thanks a lot!

  • Andrew Beckett
    in reply to zuiying

    Something odd in your environment set up - you should speak to whoever sets up the UNIX environment for accessing your Cadence tools. Anyway, glad you found the info in the documentation anyway.

    Andrew

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