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python code to compare 2 LEF

san2696

Hi all,

I have 2 LEF files i want to perform these task using python

  1. get list of Pins in first LEF and compare with other LEF and report any missing pins and any extra pins

i completed this task file size of (34000 lines). When i perform different size files its giving me error(IndexError: list index out of range)

if you find anywhere wrong in a code please correct me 

please help me to solve this problem, much much much thanks in advance 

my code(python)

file1 = open('/home/script/fileabc1.lef', 'r')     #LEF1
file2 = open('/home/script/fileabc2.lef', 'r')      #LEF2


file00 = open('/home/script/o0.txt', 'r+')
file01 = open('/home/script/o1.txt', 'r+')
file02 = open('/home/script/o2.txt', 'r+')
file03 = open('/home/script/o3.txt', 'r+')
file04 = open('/home/script/o4.txt', 'r+')

for l1 in file1.readlines():
     if 'PIN' in l1:
         file00.write("%s\n" %(l1))
             for l2 in file2.readlines():
                  if 'PIN' in l2:
                       file01.write("%s\n" %(l2))


file00_1 = file00.readlines()
file01_1 = file01.readlines()

for i in range(len(file00_1)):           
       if file00_1[i] != file01_1[i]:                # error found here
             file02.write("%s" %(file00_1[i]))
       else:
             file03.write("%s\n" %(file00_1[i]))

for i in range(len(file01_1)):
       if file01_1[i] != file00_1[i]:
             file04.write("%s\n" %(file01_1[i]))

Parents

  • A rather strange question to be asking in the "Custom IC Design" forum, since this is really a pure python question and the only IC aspect of the question is that you happen to be dealing with LEF files. I'd have thought stackoverflow or somewhere like that would be better (although this is a pretty basic python question).

    The error is pretty clear - on the line you indicated - if the second file has fewer lines than the first, then the array/list file01_1 will have fewer entries than file00_1 and hence it's inevitable that you'll get an index. 

    It rather depends on what you are trying to do, but maybe those range() calls should both be range(min(len(file00_1),len(file01_1))) ? It won't ever visit the lines after the length of the shortest file, but you'll have to adjust your code logic to handle that if that's what you want.

    Andrew

Reply

  • A rather strange question to be asking in the "Custom IC Design" forum, since this is really a pure python question and the only IC aspect of the question is that you happen to be dealing with LEF files. I'd have thought stackoverflow or somewhere like that would be better (although this is a pretty basic python question).

    The error is pretty clear - on the line you indicated - if the second file has fewer lines than the first, then the array/list file01_1 will have fewer entries than file00_1 and hence it's inevitable that you'll get an index. 

    It rather depends on what you are trying to do, but maybe those range() calls should both be range(min(len(file00_1),len(file01_1))) ? It won't ever visit the lines after the length of the shortest file, but you'll have to adjust your code logic to handle that if that's what you want.

    Andrew

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