Can we draw mutlipath different width and spacing at the same time?

Yes, with a multipart path the "offset sub paths" can certainly have different widths and separation from the master path.  Here is a brief section from the documentation on the rodCreatePath() SKILL function that you use to create a multi-part path:

rodCreatePath(
        [?name              S_name]
        ?layer              txl_layer
        [?width             n_width]
        [?pts               l_pts]
        [?justification     S_justification]
        [?offset            n_offset]
        [?endType           S_endType]
        [?beginExt          n_beginExt]
        [?endExt            n_endExt]
        [?choppable         g_choppable]
        [?cvId              d_cvId]
        [?fromObj           Rl_fromObj]
        [?size              txf_size]
        [?startHandle       l_startHandle]
        [?endHandle         l_endHandle]
        [?prop              l_prop]

        [?offsetSubPath     l_offsetSubpathArgs...]
        ;l_offsetSubpathArgs Offset Subpath Arguments
        list(
                list(
                        ?layer            txl_layer
                        [?width           n_width]
                        [?sep             n_sep]
                        [?justification   S_justification]
                        [?beginOffset     n_beginOffset]
                        [?endOffset       n_endOffset]
                        [?choppable       g_choppable]
                        [?prop            l_prop]
                        ;Repeat ROD Connectivity Arguments here
                        ) ;End of first offset subpath list
                        ...
                ) ;End of offset subpath lists
        ;End of l_offsetSubpathArgs

) ; end rodCreatePath
=> R_rodObj | nil

 I have included the arguments for the ?offsetSubPath keyword of rodCreatePath so that you can see how they are specified. It is a list of lists structure, each sublist refers to one offset sub path, but there can be multiple offset subpaths.

I hope that this answers your question.

Regards,

Lawrence.

Yes, with a multipart path the "offset sub paths" can certainly have different widths and separation from the master path.  Here is a brief section from the documentation on the rodCreatePath() SKILL function that you use to create a multi-part path:

rodCreatePath(
        [?name              S_name]
        ?layer              txl_layer
        [?width             n_width]
        [?pts               l_pts]
        [?justification     S_justification]
        [?offset            n_offset]
        [?endType           S_endType]
        [?beginExt          n_beginExt]
        [?endExt            n_endExt]
        [?choppable         g_choppable]
        [?cvId              d_cvId]
        [?fromObj           Rl_fromObj]
        [?size              txf_size]
        [?startHandle       l_startHandle]
        [?endHandle         l_endHandle]
        [?prop              l_prop]

        [?offsetSubPath     l_offsetSubpathArgs...]
        ;l_offsetSubpathArgs Offset Subpath Arguments
        list(
                list(
                        ?layer            txl_layer
                        [?width           n_width]
                        [?sep             n_sep]
                        [?justification   S_justification]
                        [?beginOffset     n_beginOffset]
                        [?endOffset       n_endOffset]
                        [?choppable       g_choppable]
                        [?prop            l_prop]
                        ;Repeat ROD Connectivity Arguments here
                        ) ;End of first offset subpath list
                        ...
                ) ;End of offset subpath lists
        ;End of l_offsetSubpathArgs

) ; end rodCreatePath
=> R_rodObj | nil

 I have included the arguments for the ?offsetSubPath keyword of rodCreatePath so that you can see how they are specified. It is a list of lists structure, each sublist refers to one offset sub path, but there can be multiple offset subpaths.

I hope that this answers your question.

Regards,

Lawrence.