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  3. How to convert string to float

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How to convert string to float

pdda
pdda over 15 years ago

I want to convert string to float.But this case is different from the other usuall convertion.

Here are details.

Example:

for( i 2 25
    
      parameters = cons(list( concat( 'w i    ) 'string  "3.0u"                               ) parameters)

    )

Now .....i want to convert all w1 to w25 string elements to floats.

Can any help me onthis.....If you need any more information .......we can talk also.

Thanks,

K.srikumar

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  • pdda
    pdda over 15 years ago

    Hi,

    My main intension is........

    for( i 2 25

     

    parameters = cons(list( concat( 'w i ) 'string "3.0u" ) parameters)

    ).............Here w2...w25 are strings

    after this.i want to use w2 ...w25 in the below line.

    Width =  get( cv~>parameters concat( 'w i ) ) - 2*cainwell

    But ........in the above line.........

    cainwell.........this variable is float and w1 .....w25 is string

    so i need convertion.......and i have to use it here.

    without convertion if i run it .......following error is comming

    *WARNING* ("difference" 0 t nil ("*Error* difference: can't handle (\"3u\" - 0.2)"))........

    Regards,

    K.srikumar.

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  • pdda
    pdda over 15 years ago

    Hi,

    My main intension is........

    for( i 2 25

     

    parameters = cons(list( concat( 'w i ) 'string "3.0u" ) parameters)

    ).............Here w2...w25 are strings

    after this.i want to use w2 ...w25 in the below line.

    Width =  get( cv~>parameters concat( 'w i ) ) - 2*cainwell

    But ........in the above line.........

    cainwell.........this variable is float and w1 .....w25 is string

    so i need convertion.......and i have to use it here.

    without convertion if i run it .......following error is comming

    *WARNING* ("difference" 0 t nil ("*Error* difference: can't handle (\"3u\" - 0.2)"))........

    Regards,

    K.srikumar.

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