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  3. automatic variable declaration in SKILL

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automatic variable declaration in SKILL

tashah
tashah over 13 years ago

 Is it possible to avoid automatic vairable declartion in SKILL? Something similar to perl's "strict".

If not, is this possible in "Scheme"?

 

Thanks.

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  • Andrew Beckett
    Andrew Beckett over 13 years ago

    Actually defstruct won't help here because you can still do:

    defstruct(myThing aProp bProp cProp)
    obj=make_myThing()
    obj->bProp => nil

    You could use an association table:

    b=makeTable('pseudoDpl)
    b->aProp=5
    b->aPorp => unbound (so it doesn't flag an error)

    But that wouldn't help you on assignment. So classes are the best way to do it, as Ted mentioned:

    defclass(myThing2 () ((aProp) (bProp) (cProp)))
    c=makeInstance('myThing2)
    c->aProp=2
    c->aPorp => *Error* slotValue: no such slot - aPorp

    Regards,

    Andrew.

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  • Andrew Beckett
    Andrew Beckett over 13 years ago

    Actually defstruct won't help here because you can still do:

    defstruct(myThing aProp bProp cProp)
    obj=make_myThing()
    obj->bProp => nil

    You could use an association table:

    b=makeTable('pseudoDpl)
    b->aProp=5
    b->aPorp => unbound (so it doesn't flag an error)

    But that wouldn't help you on assignment. So classes are the best way to do it, as Ted mentioned:

    defclass(myThing2 () ((aProp) (bProp) (cProp)))
    c=makeInstance('myThing2)
    c->aProp=2
    c->aPorp => *Error* slotValue: no such slot - aPorp

    Regards,

    Andrew.

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